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blagie [28]
3 years ago
14

I have no clue how to answer this or where to start

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0
It’s quite simple. Take the total percentage of people from this- 25*2 and add 43. It’s 93%
Andrew [12]3 years ago
5 0
You can add up the percentages. When doing this, I am also thinking that there are 100 residents in all.
From 600 to 649, there are 25 people or 25%.
From 650 to 699, there are ABOUT 45 people or 45% (43 people)
From 700 to 749, there are 25 people or 25%.
Let's add it up.
25+25+43
93
Letter A, 93%.
You might be interested in
Calculate the limit values:
Nataliya [291]
A) This particular limit is of the indeterminate form,
\frac{ \infty }{ \infty }
if we plug in infinity directly, though it is not a number just to check.

If a limit is in this form, we apply L'Hopital's Rule.

's
Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_ {x \rightarrow \infty } \frac{( ln(x ^{2} + 1 ) ) '}{x ' }
So we take the derivatives and obtain,

Lim_ {x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ \frac{2x}{x^{2} + 1} }{1}

Still it is of the same indeterminate form, so we apply the rule again,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 2 }{2x}

This simplifies to,

Lim_{x \rightarrow \infty } \frac{ ln(x ^{2} + 1 ) }{x} = Lim_{x \rightarrow \infty } \frac{ 1 }{x} = 0

b) This limit is also of the indeterminate form,

\frac{0}{0}
we still apply the L'Hopital's Rule,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ (tanx)'}{x ' }

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (x) }{1 }

When we plug in zero now we obtain,

Lim_ {x \rightarrow0 }\frac{ tanx}{x} = Lim_ {x \rightarrow0 } \frac{ \sec ^{2} (0) }{1 } = \frac{1}{1} = 1
c) This also in the same indeterminate form

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ ({e}^{2x} - 1 - 2x)'}{( {x}^{2} ) ' }

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (2{e}^{2x} - 2)}{ 2x }

It is still of that indeterminate form so we apply the rule again, to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = Lim_ {x \rightarrow0 } \frac{ (4{e}^{2x} )}{ 2 }

Now we have remove the discontinuity, we can evaluate the limit now, plugging in zero to obtain;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } = \frac{ (4{e}^{2(0)} )}{ 2 }

This gives us;

Lim_ {x \rightarrow0 }\frac{ {e}^{2x} - 1 - 2x}{ {x}^{2} } =\frac{ (4(1) )}{ 2 }=2

d) Lim_ {x \rightarrow +\infty }\sqrt{x^2+2x}-x

For this kind of question we need to rationalize the radical function, to obtain;

Lim_ {x \rightarrow +\infty }\frac{2x}{\sqrt{x^2+2x}+x}

We now divide both the numerator and denominator by x, to obtain,

Lim_ {x \rightarrow +\infty }\frac{2}{\sqrt{1+\frac{2}{x}}+1}

This simplifies to,

=\frac{2}{\sqrt{1+0}+1}=1
5 0
3 years ago
A tree casts a shadow that is 125 ft. At the same time, a 4ft tall person
jekas [21]

Answer:

100ft

Step-by-step explanation:

H over S

H over 125 then 4 over 5

cross Multiply would give you

5H = 500

500 ÷ 5 is 100

6 0
3 years ago
The volume of a cube is 4,741.632 cubic millimeters . What is The length of each side of the cube
PSYCHO15rus [73]

Answer:

790.272

Step-by-step explanation:

8 0
3 years ago
Use the distributive property to expand Negative 4 (Negative two-fifths + 3 x). Which is an equivalent expression?
Natalija [7]

Answer:

the answer is the last one

Step-by-step explanation:

so the answer is d

5 0
3 years ago
Read 2 more answers
a house was purchased for $150,000 the value decreased by 16% how much is the value of the house now​
TiliK225 [7]

Answer:

$126,000

Step-by-step explanation:

16% of 150,000 is 24,000

150,000-24,000=126,000

8 0
3 years ago
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