Question

I need help asap, I have school tomorrow and I have 4 math papers due and haven't done any of them

Answer 1

Answer:

Equation C

Step-by-step explanation:

Notice that the y-intercept is (0, 1).  Only Equations 2 and 3 have that feature.  Arbitrarily choosing x = 2 and looking up the value of y, we get y = -3.

Does this point (2, -3) satisfy Equation B?  Is -3 = -(2) + 1 true?  NO, so we eliminate Equation B and focus on Equation C:

Does the point (2, -3) satisfy Equation C?

Is -3 = -2(2) + 1 true?  Is -3 = -4 + 1 true?  YES.  So Equation C is the correct choice here.

Answer 2

Answer:

C. y = -2x + 1

Step-by-step explanation:

The equation can be represented as

y=mx+b

Where m is the slope and b is the y-intercept (if we were to plot the points on a graph, this is where the line would intercept the y-axis)

We can start by finding the slope...

$Slope = \frac{y_2-y_1}{x_2-x_1}$

We can plug in any given x, y pairs into the equation. Let's use (0, 1) and (1, -1)...

$Slope = \frac{-1-1}{1-0}=\frac{-2}{1}=-2$

The slope is -2

Now we plug this back into the equation to solve for the y-intercept...

y=-2x+b

Use any x,y coordinate pair to substitute into the equation...

1=-2(0)+b

1=0+b

b=1

Therefore the equation is...

C. y= -2x + 1