Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you! mark me as brainliest pls
§ALEX§
Answer:
C
Step-by-step explanation:
8 x 6 would equal 48, which results in not having enough money to buy lunch for more people.
Answer:
26. 14 sq.units
27. I think it's near to be 30
28. I think it is the first one
● 3x^2 - 10 = 0
Add 10 to both sides
● 3x^2 - 10 + 10 = 10
● 3x^2 = 10
Divide both sides by 3
● 3x^2/3 = 10/3
● x^2 = 10/3
● x = √( 10/3 ) or x = - √( 10/3 )
● √(10/3) + (-√(10/3)) = 0
● √(10/3) × -√(10/3) = -10/3
