Question

3x²+x=2solve by factoring ?

Answer 1

$3x^2+x=2\\\\3x^2+x-2=0\\\\3x^2+3x-2x-2=0\\\\3x(x+1)-2(x+1)=0\\\\(x+1)(3x-2)=0\\\\x+1=0\ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ 3x-2=0\\x=-1\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ 3x=2\\x=-1\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ x=\frac{2}{3}$

Answer 2

$3x^2+x=2\\ 3x^2+x-2=0\\ 3x^2+3x-2x-2=0\\ 3x(x+1)-2(x+1)=0\\ (3x-2)(x+1)=0\\ x=\frac{2}{3} \vee x=-1$