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stich3 [128]
3 years ago
5

3x²+x=2solve by factoring ?

Mathematics
2 answers:
lara [203]3 years ago
8 0
3x^2+x=2\\\\3x^2+x-2=0\\\\3x^2+3x-2x-2=0\\\\3x(x+1)-2(x+1)=0\\\\(x+1)(3x-2)=0\\\\x+1=0\ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ 3x-2=0\\x=-1\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ 3x=2\\x=-1\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ \ \ \ x=\frac{2}{3}\\\\
kondor19780726 [428]3 years ago
7 0
3x^2+x=2\\
3x^2+x-2=0\\
3x^2+3x-2x-2=0\\
3x(x+1)-2(x+1)=0\\
(3x-2)(x+1)=0\\
x=\frac{2}{3} \vee x=-1
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