Given:
bisects ∠RST.
To find:
The 
.
Solution:
Since, bisects ∠RST, therefore
...(1)
Now,
[Using (1)]
![[\text{Given }m\angle RSV=64^\circ]](https://tex.z-dn.net/?f=%5B%5Ctext%7BGiven%20%7Dm%5Cangle%20RSV%3D64%5E%5Ccirc%5D)
Therefore, the value of is 
.
6.3c-2(1.5c+4.1)=6.3c-3c-8.2=3.3c-8.2 :))))
Answer:
x²(9x– 11)(9x + 11)
Step-by-step explanation:
81x⁴ – 121x²
The expression can be factorised as follow:
81x⁴ – 121x²
x² is common to both term. Thus:
81x⁴ – 121x² = x²(81x² – 121)
Recall:
81 = 9²
121 = 11²
Therefore,
x²(81x² – 121) = x²(9²x² – 11²)
= x²[(9x)² – 11²]
Difference of two squares
x²(9x– 11)(9x + 11)
Therefore,
81x⁴ – 121x² = x²(9x– 11)(9x + 11)
Answer:
cool
Step-by-step explanation:
i’m pretty positive you would just subtract!
