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3 years ago

9

131.39 g/mol C2HCl3 find the molecular formulas

1 answer:

Art [367]3 years ago

5 0

Answer:

Find the mass of 1 mole.

mass of

1

mole of

131.39

g

m

o

l

C

2

H

C

I

⋅

3

=

37.04000067

g

Explanation:

hope it helps make brainlliest ty

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Consider the following reaction. SO2Cl2 → SO2 + Cl2. After collecting experimental data you found that plotting ln[SO2Cl2] vs. t

Nikitich [7]

Answer:

$[SO_2Cl_2]_{600}= 0.0842 M$

Explanation:

Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to $SO_2Cl_2$ .

The linear equation has the following terms:

$y = -0.000290t - 2.30$

It is a linear form of the integrated first-order law equation:

$ln[SO_2Cl_2]_t = -kt + ln[SO_2Cl_2]_o$

Therefore, the rate constant, k, is:

$k = 0.000290 s^{-1}$

The natural logarithm of initial molarity is:

$ln[SO_2Cl_2]_o = -2.30$

Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:

$ln[SO_2Cl_2]_{600} = -0.000290 s^{-1}\cdot 600 s - 2.30 = -2.474$

Take the antilog of both sides to find the actual molarity:

$[SO_2Cl_2]_{600}=e^{-2.474} = 0.0842 M$

4 0

3 years ago

Put an x of it is a physical property but of it is a chemical propety pit a +

makkiz [27]

Density=a+
Flammability=a
Solubility=a
Reacts with acid to form H2=a+
Support combustion=a+
Sour taste=a
Melting point=a
Boiling point=a
Hardness=a
luster=a+
Odor=a
Maleability =a
Shiny=a

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3 years ago

The branch of chemistry that looks at the release of electrical energy is called

sergij07 [2.7K]

B is the correct answer tbh

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3 years ago

The molarity of a 4.200 L solution is 1.230 M Na2CO3. What is the mass of Na2CO3

Lerok [7]

Answer:

547.5g

Explanation:

To get the mass, you need moles.

moles = (molarity)(Liters)

moles = (1.230M)(4.200L) = 5.166 moles Na2CO3

Now, just use stoichiometry

molar mass of Na2CO3 = 2(mass of Na) + (mass of C) + 3(mass of O)

= 2(22.9) + 12.01 + 3(16) = 105.99g/mol

5.166moles(105.99g/mol)

= 547.544

But, the measurements given had 4 significant figures, so in chemistry we write:

547.5g

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3 years ago

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DIA [1.3K]

Answer: it’s b)

Explanation: that’s the only difference that is listed

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3 years ago

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