At a temperature of 30 deg C, the vapour pressure of water
H2O is about 32 mm Hg. Therefore at a total pressure f 734 mm Hg, the partial
pressure of the Hydrogen gas collected is:
<span>P Hydrogen = 734 mm Hg – 32 mm Hg = 702 mm Hg</span>
A3B2 because the oxidation numbers are the same as ionic charge just switch symbol and number. Then use the cross cross method and you get A3B2.
I think it’s A because each unit is worth 3
1 mol of any particles has 6.02 * 10 ²³ particles.
If we look at 1 NH3 (1 mol NH3 or 1 molecule NH3), we can see that 1 molecule NH3 has 1 atom of N and 3 atoms of H; also 1 mole of NH3 has 1 mole of N atoms and 3 moles of H atoms.
So, 1 mol of NH3 has 1 mol of N atoms,
and 2.79 mol NH3 have 2.79 mol of N atoms.
2.79 mol of N atoms* 6.02 * 10 ²³ N atoms/ 1 mol N atoms = 1.68*10²⁴ N-atoms
Answer is 1.68*10²⁴ N-atoms.
good luck with that. I thought I had it, but it was not right.
