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fiasKO [112]
3 years ago
5

A flexible container is put in a deep freeze. Its original volume is 3.00 m3 at 25.0°C. After the container cools, it has shrunk

to 2.00 m3. Its new temperature in degrees Celsius is
Chemistry
1 answer:
Goryan [66]3 years ago
5 0
This is an ideal gas problem. The gas inside the balloon is considered ideal. Ideal gas equation is a function pressure, temperature, amount and volume. Note: amount is constant since the balloon ins closed. Pressure is maintained constant since the walls are flexible. Ideal gas equation is: PV=nRT. Put all constant in one side and variables in one. 

P/nR=T/V. To find the answer to the question equate the constants of both situation 
T1/V1=T2/V2
(25+273.15)/3=(x+273.15)/2
x=-74.38 degC 
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With 21 g of Zinc, and 7 g of CuCl2, how much ZnCl2 is made in grams?
mina [271]

Answer: 7.07 grams

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

\text{Moles of} zinc=\frac{21g}{65g/mol}=0.32moles

\text{Moles of} CuCl_2=\frac{7g}{134g/mol}=0.052moles

Zn+CuCl_2\rightarrow Cu+ZnCl_2

According to stoichiometry :

1 mole of CuCl_2 require 1 mole of Zn

Thus 0.052 moles of CuCl_2 will require=\frac{1}{1}\times 0.052=0.052moles  of Zn

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Zn is the excess reagent.

As 1 mole of CuCl_2 give = 1 mole of ZnCl_2

Thus 0.052 moles of CuCl_2 give =\frac{1}{1}\times 0.052=0.052moles  of ZnCl_2

Mass of ZnCl_2=moles\times {\text {Molar mass}}=0.052moles\times 136g/mol=7.07g

Thus 7.07 g of ZnCl_2 will be produced from the given masses of both reactants.

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