The San Andreas fault puts Californians at great risk for major earthquakes and tsunamis. True False
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corrected question:The heavyweight boxing champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 26.5 m/s in 0.044 s . The mass of the paper is 0.003 kg. Part A Find the force of the punch on the paper
Answer:
Force=1.8N
Explanation:
Newtons third law states that in every action there is equal and opposite reaction.
The force of the punch will be the force that moves the paper by a speed of 26.5m/s.
m=0.003kg , v=26.5m/s u=0(the paper is punched from rest) t=0.044s
F=1.8N
Answer:
The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.
Explanation:
Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
So the density of silver is 10.49 g / mL indicates that 10.49 g occupies a volume of 1 mL. Then a rule of three can be applied in the following way: if in 1 mL a mass of 10.49 g is occupied, in 87.75 mL how much mass will it occupy?
mass= 920.5 g
<u><em> The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.</em></u>
The forces a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.
<h3>What is force?</h3>Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The application of a force may be used to describe the steel as an elastic element within a certain range of applied force.
Given data;
Young modulus, E=2.10 × 10¹¹ N/m²
Cross-sectional area,A
Final length,
Initial length,
Hence, the force a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.
To learn more about the force refer to the link;
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