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Crazy boy [7]
3 years ago
14

A rope is attached to a hook in the ceiling and is hanging straight down. The rope has a mass m, and nothing is attached to the

free end of the rope. As a transverse wave travels down the rope from the top, ________________.
Physics
1 answer:
Andru [333]3 years ago
6 0

As a transverse wave travels down the rope from the top, the speed of the wave decreases. In a transverse wave, movement occurs at right angles.

<h3>What is a transverse wave?</h3>

A transverse wave can be defined as a type of wave where movement occurs at right angles to the direction of the wave.

Some examples of types of transverse waves include, among others, seismic waves, radio waves, and light waves.

The ripples on the surface of water move at right angles to the direction of the wave, thereby they represent transverse waves.

Learn more about transverse waves here:

brainly.com/question/13761336

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Qual a capacidade térmica de um objeto que, ao receber 10000 cal de energia, tem sua temperatura elevada de 25°C para 75°C?
Stolb23 [73]

Answer:

200 cal/^{\circ}C

Explanation:

When heat energy is supplied to an object, the temperature of the object increases according to the equation:

Q=C\Delta T

where

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\Delta T is the change in temperature

In this problem we have:

Q=10,000 cal is the energy supplied

\Delta T=75C-25C=50C is the change in temperature of the object

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3 years ago
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3 years ago
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
cluponka [151]

Answer:Highest frequency  =618.89Hz

Lowest frequency=582.22Hz

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Vs = rω  where

r = the radius of circular path = 1.0 m

ω is the angular velocity of the sound generator. = 100 rpm

1 rev/min = 0.10472 rad/s

100rpm =10.472 rad/ s

Vs = rω

= 1m x 10.472rad/ s=  10.472m/s

A) Highest frequency  heard by a student in the classroom = Maximum frequency. Using the Doppler effect formulae,

f max = (v/ v-vs) fs

Where , v is the speed of the sound in air at 20 degrees celcius =

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fs is the frequency of the sound generator= 600 Hz

f max = (343/ 343 - 10.472) x 600

=343/332.528) x600

=618.89Hz

B) Lowest frequency  heard by a student in the classroom = Minimum frequency

f min = (v/ v+vs) fs

(343/ 343 + 10.472) x 600

=343/353.472) x 600

=582.22hz

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3 years ago
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