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Dennis_Churaev [7]
3 years ago
12

What mass of silver will occupy a volume of 87.75 mL?The density of silver is 10.49 g/mL.​

Physics
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.

Explanation:

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

So the density of silver is 10.49 g / mL indicates that 10.49 g occupies a volume of 1 mL. Then a rule of three can be applied in the following way: if in 1 mL a mass of 10.49 g is occupied, in 87.75 mL how much mass will it occupy?

mass=\frac{87.75 mL*10.49 g}{1 mL}

mass= 920.5 g

<u><em> The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.</em></u>

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Givens
=====
V = 4.00 L
T = 273oK We're assuming the temperature does not change, just the pressure.
n = 0.864 moles
R = 8.314 joules / mole  * oK
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Formula
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PV = n*R*T
P = n*R*T/V
P = 0.864 * 8.314 * 273 / 4
P = 490 kpa


You have to add 1.6 – 0.864 = 0.736 moles of gas.


We have to assume that the temperature and pressure remain the same when we add the 0.736 moles of gas. We are now looking for the volume.


PV = n*R*T

<span> V = 0.736 * 8.314 * 273 / 490</span>

V = 3.41 L Remember this is at about 4 atmospheres so we have to convert to Standard Pressure.

Total Volume = 3.41 + 4.00 = 4.41


V1 * P1 = V2 * P2

P1 = 490 kPa

P2 = 101 kPa

V1 = 7.41 L

V2 = ????


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<span>You had 4 L now you need 31.94 more.</span> 
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A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is
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Explanation:

It is given that,

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Amplitude of the oscillation, A = 7.5 cm = 0.075 m

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Time, t = 15 s

(a) Let m is the mass of the ball. The frequency of oscillation of the spring is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

Total number of oscillation per unit time is called frequency of oscillation. Here, f=\dfrac{31}{15}=2.06\ Hz

m=\dfrac{k}{4\pi^2f^2}

m=\dfrac{15}{4\pi^2\times 2.06^2}

m = 0.0895 kg

or

m = 89 g

(b) The maximum speed of the ball that is given by :

v_{max}=A\times \omega

v_{max}=A\times 2\pi f

v_{max}=0.075\times 2\pi \times 2.06

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v_{max}=97\ cm/s

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