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Dennis_Churaev [7]
2 years ago
12

What mass of silver will occupy a volume of 87.75 mL?The density of silver is 10.49 g/mL.​

Physics
1 answer:
Anastaziya [24]2 years ago
5 0

Answer:

The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.

Explanation:

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

So the density of silver is 10.49 g / mL indicates that 10.49 g occupies a volume of 1 mL. Then a rule of three can be applied in the following way: if in 1 mL a mass of 10.49 g is occupied, in 87.75 mL how much mass will it occupy?

mass=\frac{87.75 mL*10.49 g}{1 mL}

mass= 920.5 g

<u><em> The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.</em></u>

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a

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b

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Explanation:

From the question we are told that

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The  apparent weight of the passenger at the lowest point is mathematically represented as

           F_A_L  =  F_c  + W

Where  F_c is the centripetal force on the passenger,  which is mathematically represented as

         F_c  =m *  r *  w^2

Where w is the angular velocity which is mathematically represented as

         w =  \frac{2* \pi   }{T}

substituting values

         w =  \frac{2* 3.142 }{24}

         w =  0.2618 \ rad/s

and  r  is the radius which is evaluated as r =  \frac{d}{2}

   substituting values

         r =  \frac{24.383}{2}

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So

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          F_c  =  33.42 \ N

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           W =  40 * 9.8

           W =  392 \ N

So

         F_A    =  33.42 + 392

         F_A  =425.42 \ N

The  apparent weight of the passenger at the highest point is mathematically represented as

          F_A_H  =  W- F_c

substituting values

         F_A_H  = 392 -  33.42

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