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lina2011 [118]
3 years ago
12

Which of the following has a stabilizing effect on equilibrium? A. Intraspecific competition B. Niches C. Interspecific competit

ion D. Evolution
Biology
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

The answer is option A "Intra-specific competition"

Explanation:

The equilibrium properties of an added substance multi-locus model of a quantitative attribute under recurrence and thickness subordinate determination are examined. Two contradicting transformative forces are expected to act:

1. settling determination on the attribute, which favors genotype with a middle aggregate, and

2. Intraspecific competition interceded by that quality, which favors genotype whose impact on the attribute digresses most from that of the overall genotype.

Likewise, wellness of genotypes have a recurrence free part depicting balancing out choice and a recurrence and thickness subordinate segment demonstrating competition.

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Fish that feed on sediment will most likely be found in _______ rivers. a. shallow b. narrow c. deep d. fast-moving
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Answer:

The correct answer is - option C. Deep.

Explanation:

The river with a narrow river channel found in shallow depth rivers that show relatively faster water flows than the deeper river that are slow in the water flow. In the shallow rivers sediments found in suspended mode and transported to the sea or delta and deposited there.

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3 0
4 years ago
Read 2 more answers
A population is in Hardy-Weinberg Equilibrium with respect to a gene, "yellow," which has 2 alleles, y and Y. Y, the wild type a
Anton [14]

Answer:

The frequency of the Y allele is 0.7

The frequency of the y allele is 0.3

The frequency of the YY homozygote is 0.49

The frequency of the Yy heterozygote is 0.42

Explanation:

According to Hardy-Weinberg Equilibrium,

p + q = 1

p² + 2pq + q² = 1

where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of dominant homozygous genotype

2pq = frequency of heterozygous genotype

q² = frequency of  recessive homozygous genotype

Here,

yy = q² = 0.09

frequency of y allele = q = √0.09 = 0.3

frequency of Y allele = p = 1-q = 1-0.3 = 0.7

p² = YY = (0.7)² = 0.49

2pq = Yy = 2 * 0.7 * 0.3 = 0.42

7 0
4 years ago
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