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tatyana61 [14]
2 years ago
8

-2(x+4) Help find answers

Mathematics
2 answers:
MAVERICK [17]2 years ago
3 0
Answer=-2x-8 yeah that should be ur answer
lions [1.4K]2 years ago
3 0

Answer:

-2x - 8

Step-by-step explanation:

Multiply each term in parentheses by -2 : -2x - 2 · 4

Multiply the numbers: -2x - 8

Soultions : -2x - 8 :)

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Which equation can you use to find the value of x?
Vadim26 [7]

Answer:

I would say bottom left

Step-by-step explanation:

It is the most plausible to the equation

5 0
3 years ago
Read 2 more answers
A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
4. A boat sails east for 35 miles and then turns to sail 10 miles south. What is the distance of the boat from its ending point
Elden [556K]

Answer:

36.4mi

Step-by-step explanation:

The boat sailed two legs of a right-angled triangle.

The distance from the starting point is the hypotenuse of the triangle.

d = √(35² + 10²)

  = √(1225 + 100)

  = √1325

  = 36.4 mi

5 0
3 years ago
26. Find (g-|(2). Use f(x) = 2x – 1 and g(x) = x + 5.<br> a. 4<br> b. 2<br> c. 4.<br> d. 6
schepotkina [342]

Answer:

4dyhdhdjdjjddhjdjdhdudhf

5 0
3 years ago
ANSWER THIS QUICKLY PLEASE!!!!!!!
Effectus [21]
Hi
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