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user100 [1]
3 years ago
11

Is smoke chemically combined?​

Chemistry
1 answer:
Romashka [77]3 years ago
8 0

Answer:

yes smoke is chemically combined because smoke is a collection of airborne solid and liquid particles and gases released when a material burn.

hope it is helpful to you

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What is a concave structure
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A concave<span> surface, </span>structure<span>, or line. tr.v. con·caved, concaving, con·caves. 
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Water vapor in the morning turns into dew on the grass.
Valentin [98]

Answer:

is that a question or statement?

Explanation:

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Please help i will mark brainlist
Sphinxa [80]

Answer:

V= 21 cubic cm (( I am not sure about density ))

Explanation:

V= L×W×H

4 0
3 years ago
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Calculate the mass of oxygen gas (O2) dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air. Assume the
Ilia_Sergeevich [38]

Answer:

The mass of oxygen gas dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air is 0.04936 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{gas}=K_H\times p_{gas}

where,

K_H = Henry's constant =

p_{O_2} = partial pressure of oxygen

We have :

Pressure of the air = P

Mole fraction of oxygen in air = \chi_{O_2}=0.210

p_{O_2}=P\times \chi_{O_2}

=0.210\times 1.13 atm= 0.2373 atm

K_H = Henry's constant = 1.30\times 10^{-3}M/atm

Putting values in above equation, we get:

C_{O_2}=1.30\times 10^{-3}M/atm\times 0.2373  atm\\\\C_{O_2}=0.003085 M

Moles of oxygen gas = n

Volume of water = V = 5 L

Molarity = \frac{Moles}{Volume(L)}

0.003085 M=\frac{n}{5 L}

n = 0.003085 M\times 5 L=0.001542 mol

Mass of 0.001542 moles of oxygen gas:

0.001542 mol × 32 g/mol = 0.04936 g

The mass of oxygen gas dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air is 0.04936 grams.

5 0
3 years ago
A compressor takes 0.50 m3 of a gas at 33°C and 760 mm Hg and compresses it to 0.10 m3, cooling it to -55°C at the same time. Wh
weqwewe [10]

The pressure of the gas is 2700 mmHg.

To solve this problem, we can use the <em>Combined Gas Laws</em>:

(<em>p</em>_1<em>V</em>_1)/<em>T</em>_1 = (<em>p</em>_2<em>V</em>_2)/<em>T</em>_2

<em>p</em>_2 = <em>p</em>_1 ×<em> V</em>_1/<em>V</em>_2 × <em>T</em>_2/<em>T</em>_1

<em>T</em>_2 = (-55+273.15) K = 218.15 K; <em>T</em>_1 = (33+273.15) K = 306.15 K

<em>p</em>2 = 760 mmHg × (0.50 m^3/0.10 m^3) × (218.15 K/306.15 K) = 2700 mmHg

5 0
3 years ago
Read 2 more answers
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