(3) The concen<span>tration of the solution remains constant.</span>
Answer:
Mass = 217.30 g
Solution:
Mass and moles are related to each other as,
Moles = Mass / M.mass ---- (1)
Where;
Moles = 3.42
M.Mass = 63.54 g.mol⁻¹
Solving eq. 1 for Mass,
Mass = Moles × M.mass
Putting Values,
Mass = 3.42 mol × 63.54 g.mol⁻¹
Mass = 217.30 g
Answer:6.94
Explanation:
Molar mass of CaCO3=40+12+16×3
=40+12+48=100g/mol
Moles=mass of substance/molar mass
=97mg/100g=0.097/100=0.00097moles/L.
PH=-log[CaCo3]=-log(0.00097)=6.94
P.s it's log to base e
