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Valentin [98]
3 years ago
8

The combustion method used to analyze for carbon and hydrogen can be adapted to give percentage N by collecting the nitrogen fro

m combustion of the compound as N2. A sample of a compound weighing 8.75 mg gave 1.59 moL N2 at 25 C and 749 mmHg. What is the percentage N in the compound
Chemistry
1 answer:
12345 [234]3 years ago
6 0

Answer:

The percentage of N in the compound is 0.5088

Explanation:

Mass of compound = 8.75 mg = 8.75×1000 = 8750 g

Mass of N2 = number of moles of N2 × MW of N2 = 1.59 × 28 = 44.52 g

% of N in the compound = (mass of N2/mass of compound) × 100 = (44.52/8750) × 100 = 5.088×10^-3 × 100 = 0.5088

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A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v
Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

0.9762bar.\frac{1atm}{1.013bar} =0.9637atm

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81  × 10⁻³ moles of M reacted. The molar mass of the metal is:

\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol

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4 years ago
Use the reading below to answer the question.
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Answer: I think it is amount of rainfall

Explanation:

8 0
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Which of the following is least likely to be a base?
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The answer it is most likely to be is b lol
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2 years ago
16. A formula unit indicates the simplest unit of a(n)
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The average density of a carbon-fiber-epoxy composite is 1.615 g/cm3. the density of the epoxy resin is 1.21 g/cm3 and that of t
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The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.

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a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
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