I think it is D
Hope my answer help you?!
The way i solved the probability percentage was 3/4 = x/100, which means his probability of making it in the goal was 75%. if it was out of five, he’d make 3.75 goals, going by the percentage. hope this helps you in some way
Given that the equation to find the height of the firework is
h(t) = at² + vt + h₀
with a = -16 ft/s² and v = 128 ft/s. In addition, since the firework starts from the ground, then the initial height, h₀, is equal to 0. Substituting these values, we have
h(t) = -16t² + 128t + 0 = -16t² + 128t
Seeing that h(t) is a quadratic function, then it forms a parabola. To find its maximum height, we can compute for the parabola's vertex.
To find the vertex's x-coordinate, we can use
t = -b/2a = (-128)/(2 · -16) = -128/-32 = 4
Since, it takes 4 seconds for the firework to reach its maximum height, then the maximum height it reaches is equal to h(4). Hence, we have
h(4) = -16(4)² + 128(4) = -16(16) + 512 = 256
Hence, the highest that the firework can reach is equal to 256 ft.
Answer: A. 256 ft
Answer:
y = 0.7(x^2 - 64x - 576)
Average rate of change = -49.
Step-by-step explanation:
As the x intercepts are -8 and 72 we can write the equation
y = a(x + 8)(x - 72) where a is some constant to be found.
As it passes through point (62, -490) we have, substituting:
-490 = a(62+8)(62-72)
-490 = - 700a
a = 0.7
So the equation of the parabola
y = 0.7(x + 8)(x - 72) or
y = 0.7(x^2 - 64x - 576).
Average rate of change between x = -8 and x = 2
= [0.7(2+ 8)(2 - 72) - 0.7(-8+8)(-8-72)] / (2 - -8)
= -490 - 0 /10
= -49
Answer:
Maybe yawl can help me on this one too because i do not know this.
Step-by-step explanation: