Let the length of the shortest side = x
The two longer sides that are equal = 3x
The are two equal longer sides, so their total is 3x + 3x = 6x
3x+ 3x + x= 35 Collect like terms on the left
7x = 35 Divide by 7 on both sides
x = 35/7
x = 5
Answer
Two long sides -- 15 cm each
Shortest side -- 5 cm
<h3>The terms 4x and 5y has different variable present in it.

</h3>
<em><u>Solution:</u></em>
Given that,

<em><u>The reason is:</u></em>
When we are adding terms which has exactly the same variables, we must add the constants and let the result stand with variable
Which means,
4x + 10x = 14x
But,
We cannot add terms that has different variable
Which means,
4x + 5y
Here, both the terms 4x and 5y has different variable present in it. Hence they cannot be added together

Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
__
In many cases, it is preferred to keep the power inside the radical symbol.
Answer:
1:4 or 1/4
Step-by-step explanation:
9 cm : 36 cm
They both can be divided by 9 so,
9 ÷ 9 : 36 ÷ 9
= 1 : 4
Hope this helps