The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so, given the point (-2,8)
x1=-2
y1=8
y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8
Answer:2.47
Step-by-step explanation:
cuz i have the same homework
Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
P = 0.5Q - 20
Step-by-step explanation:
P = kQ + c
substitute Q = 60 , P = 10 into the equation
10 = 60k + c → (1)
substitute Q = 240, P = 100 into the equation
100 = 240k + c → (2)
subtract (1) from (2) term by term to eliminate c
90 = 180k ( divide both sides by 180 )
=
= 0.5 = k
substitute k = 0.5 into (1) and solve for c
10 = 60(0.5) + c
10 = 30 + c ( subtract 30 from both sides )
- 20 = c
then
P = 0.5Q - 20
Answer:
x=5.2
Step-by-step explanation:
8x−14=7.7x+3x
Step 1: Simplify both sides of the equation.
8x−14=7.7x+3x
8x+−14=7.7x+3x
8x−14=(7.7x+3x)(Combine Like Terms)
8x−14=10.7x
8x−14=10.7x
Step 2: Subtract 10.7x from both sides.
8x−14−10.7x=10.7x−10.7x
−2.7x−14=0
Step 3: Add 14 to both sides.
−2.7x−14+14=0+14
−2.7x=14
Step 4: Divide both sides by -2.7.
−2.7x
/−2.7 =
14
/−2.7
x=−5.185185 or 5.2