Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
P(7, -7)
Step-by-step explanation:
Xp = 6+ ⅓(9-6)= 6+ ⅓(3)=6+1 =7
Yp = -10 + ⅓(-1+10)= -10+⅓(9)= -10+3=-7
=> P (7, -7)
Step-by-step explanation:
2x - 5 = y - 5
2x = y
x = y/2
y - 3 = x + 1
Substitute the value of x here,
y - 3 = 
y - 3 = 
2y - 6 = y + 2
y = 8
Now, x = 8/2
x = 4
So, go for D part, it is the correct answer.
Good Night/Day !
Answer:
The answer to the first one is number 2
Step-by-step explanation:
They are parralel because they do not cross either in the front or in the back
Answer:
They are adding 16 to the number each time. So the next number in the sequence would be 78.
Step-by-step explanation:
d(1) = 14
d(n) = d (n-1) + 16
14 + 16 = 30
30 + 16 = 46
46 + 16 = 62
62 + 16 = 78 and so on...
