A lady falling has a final velocity of 4m/s
v = 4m/s
Mass of the lady is 60kg.
m = 60kg
Using conservation of energy, the potential energy of the body from the point where the lady is dropping is converted to the final kinetic energy of the lady.
P.E = K.E(final) = ½mv²
P.E = ½ × 60 × 4²
P.E = 480 J.
Buoyant force = 3.0 N
The object will not float.
Apparent weight of a body immersed in water is the actual weight of object minus buoyant force
Given in the question that;
Weight of object in air = 7.0 N
Apparent weight of object = 4.0 N
4.0 N = 7.0 N - Buoyant force
Buoyant force = 7.0 - 4.0 = 3.0 N
In this case, the buoyant force is less than weight of the object thus the object will sink.
i dont know!
C) The lander’s velocity decrease toward the reference.
took the test
Heat absorbed by the engine:
Heat rejected by the engine:
Now the efficiency of the engine:
Now the Carnot efficiency of the engine: