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Zepler [3.9K]
3 years ago
12

Name the Organs and functions of digestive system

Physics
1 answer:
Alexxx [7]3 years ago
6 0
You forgot to add a photo.
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Does anyone understand This question if you do can you tell me the answer
leonid [27]

Answer:

50N increasing

Explanation:

it looks like we want the net force. this is the sum of all forces acting on the object. here the problem is extremely simplified and we are even given the values of force. this looks like the rocket is producing an upward force of 160 newtons. it also looks like maybe weight (gravity) and drag (air resistance) are producing downward force against the rocket. we can say those would be subtracting from the amount of upwards force. so 160-40-70=50N. since the force is positive that means we will still have a magnitude of force vector that points upward and so we will increase.

6 0
3 years ago
What grade of sprain is a completely torn ligament?
sattari [20]

Knee sprains can be classified into three grades, depending on the amount of damage: Grade 1: a few fibres (less than 10%) are damaged/torn. Usually heals naturally. Grade 2: more fibres are torn but the ligament is still intact. Grade 3: the ligament is ruptured ie completely torn.

:)

5 0
3 years ago
Read 2 more answers
Ammonia enters the compressor of an industrial refrigeration plant at 2 bar, −10°C with a mass flow rate of 15 kg/min and is com
Juli2301 [7.4K]

Answer:

a) W=85.225 kW

b) 0.02\frac{kW}{K}

Explanation:

First, consider the energy balance for the compressor: The energy that enters to the system (W and enthalpy of the feed flow) is equal to the energy that goes out from it (Heat Q and enthalpy of the exit flow):

W+m*h_1=Q+m*h_2\\W=Q+m*(h_2-h_1)

Consider the enthalpy data from van Wylen 6th edition, Table B.2.2. According to that, h_1=h(200kPa,-10C)=1440.6\frac{kJ}{kgK},  h_2=h(1200kPa,140C)=1757.5\frac{kJ}{kgK}

So, the power input to the compressor is:

W=6kW+15\frac{kg}{min}*\frac{min}{60s}*(1757.5-1440.6)\frac{kJ}{kg}\\W=85.225kW

b) The differential entropy change dS for a reversible heat transfer dQ at a temperature T is:

dS=\frac{dQ}{T}

This equation can be integrated if the heat transfer surface temperature remains constant, which is the case, giving as a result:

S_2-S_1=\frac{Q}{T}=\frac{6kW}{300K}=0.02\frac{kW}{K}

6 0
3 years ago
A lever is used to lift a boulder. The fulcrum is placed 1.60 m away from the end at which you exert a downward force, producing
KengaRu [80]
Ion even know maybe a,b,c,
5 0
3 years ago
Vector A points north and vector B points east. If c = B - A , then vector C points where?
Sergio [31]

Answer:

South of East

Explanation:

7 0
3 years ago
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