Answer:
Option (B)
Explanation:
The volatile substances are usually referred to those substances that can be easily evaporated into the atmosphere at normal temperature. Some of the common volatile present in the molten materials such as magma are H₂O, CO₂, H, N, CH₄, and SO₂.
These volatile substances are found to be mixed with the magma, which is commonly known as the molten material. When this magma comes out to the surface, the pressure decreases, and it escapes into the atmosphere forming bubbles, and these are harmful gases that are harmful to the atmosphere.
Thus, the correct answer is option (B).
Oxidation is a process in which electrons are lost from the substance. Since electrons are lost, oxidation state increases.
In the above reaction, we can see that oxidation state increases for Mn from 0 to +2. That mean Mn is undergoing oxidation.
We have
The oxidation state decreases for Cu, that means Cu undergoes reduction.
The formula to calculate cell potential is
Let us plug in the given Eox and Ered values.
The overall cell potential is +1.52V
The change in temperature had the greatest effect at changing the volume of the balloon.
<h3>What are the gas laws?</h3>
The gas laws are used to describe the parameters that has to do with gases.
Given that;
P1 = 98.5 kPa
T1 = 18oC or 291 K
V1 = 74.0 dm3
P2 = 7.0 kPa
V2 = ?
T2 = 18oC or 291 K
P1V1/T1 = P2V2/T2
P1V1T2 =P2V2T1
V2= P1V1T2/P2T1
V2 = 98.5 kPa * 74.0 dm3 * 291 K/ 7.0 kPa * 291 K
V2 = 1041.3 dm3
When;
V1 = 1041.3 dm3
T1 = 291 K
V2 = ?
T2 = 80oC or 353 K
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2 = 1041.3 dm3 * 353 K/291 K
V2 = 1263 dm3
The change in temperature had the greatest effect at changing the volume of the balloon.
Given that
V1 = 100 cm^3
T1 = 273 K
P1 = 1.01 * 10^5 Pa
V2 = ?
P2 = 3.00 x 10^-4 Pa
T2 = -180oC or 255 K
V2= P1V1T2/P2T1
V2 = 1.01 * 10^5 Pa * 100 cm^3 * 255 K / 3.00 x 10^-4 Pa * 273 K
V2 = 3.14 * 10^10 cm^3
Learn more about gas laws:brainly.com/question/12669509
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