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Makovka662 [10]
3 years ago
11

Need help solving #7 please

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

False

Step-by-step explanation:

The equation says 21 is greater than or equal to 27, so it is false

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The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they
Anvisha [2.4K]

Answer: 0.9726

Step-by-step explanation:

Let x be the random variable that represents the distance the tires can run until they wear out.

Given : The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they wear out is a normally distributed random variable with a \mu=67,000 miles and a \sigma= 5,200 miles.

Then , the probability that a tire wears out before 60,000 miles :

P(x  [using p-value table for z]

Hence, the probability that a tire wears out before 60,000 miles= 0.9726

8 0
3 years ago
Have another question for you guys it is in the image
Lerok [7]

Answer:

A because its supposed to be on the y axis

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3 years ago
Enter the answer to the nearest tenth. Another home business has an average income of $1.200.00 per month with a standard deviat
Nonamiya [84]

Answer: -1.7

Step-by-step explanation:

Given : Another home business has an average income of $1.200.00 per month with a standard deviation of $100.00.

i.e.\mu=\$1200.0

\sigma=\$100.00

Let x represents the monthly income.

Since . z=\dfrac{x-\mu}{\sigma}

For x= 1030 , we have

z=\dfrac{1030-1200}{100}=-1.7

Hence, the required z-score = -1.7

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3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
HELP FAST PLEASE! ILL GIVE 20 POINTS PLUS BRAINLIEST!!!!
pav-90 [236]

Answer:

  see below

Step-by-step explanation:

The recursive function tells you the first term is 1. That is the meaning of ...

  a_1=1

It also tells you that to find the next term, you multiply this term by 1/2:

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And, to find the next term, you multiply this term by 1/2:

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Then the first three terms are ...

  1, 1/2, 1/4

4 0
4 years ago
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