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puteri [66]
3 years ago
8

Jack is age 45 and owns a self-only high deductible health policy with a $7,000 deductible under his HSA. What is his maximum pe

rmitted HSA contribution in 2020?
Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

Answer:

$3350

Step-by-step explanation:

HSA holders have the opportunity to keep a certain amount in reserve up to $3350 for an individual and $6650 for a family. Those that are 55 and older have the opportunity to accumulate an additional $1000 which implies that $4350 per individual and $7650 per family, in which these contributions require 100% tax -deductible at gross income.

Thus, the maximum permitted HSA contribution in 2020 for Jack is $3350.

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Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leap
stepladder [879]

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

The height of the dolphin after t seconds is given by:

h(t) = -16t^2 + 96t - 128

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which h(t) = 0 it crosses the surface upwards, and then the second time for which h(t) = 0 it crosses the surface downwards.

We have to find these roots. So

h(t) = -16t^2 + 96t - 128

-16t^2 + 96t - 128 = 0

Multiplying by -16

t^2 - 6t + 8 = 0

\Delta = (-6)^{2} - 4*1*8 = 36 - 32 = 4

t_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

t_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

4 - 2 = 2

The dolphin will be above the surface of the water for 2 seconds.

4 0
3 years ago
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