If A = {2, 3, 4, 5} B = {4, 5, 6, 7} C = {6, 7, 8, 9} D = {8, 9, 10, 11}, find (A ∪ B) ∪ C
Iteru [2.4K]
Answer:
(AUB)UC=2,3,4,5,6,7,8,9
put all these numbers inside curly bracket
Step-by-step explanation:
Answer:
Recursive rule for arithmetic sequence = an = a[n-1] + 3
Step-by-step explanation:
Given arithmetic sequence;
-7, -4, -1, 2, 5, …
Find:
Recursive rule for arithmetic sequence;
Computation:
Let a1 = -7
So,
⇒ a2 = a1 + 3 = -4
⇒ a3 = a2 + 3 = -1
⇒ a4 = a3 + 3 = 2
⇒ a5 = a4 + 3 = 5
So, the recursive formula is
⇒ an = a[n-1] + 3
Recursive rule for arithmetic sequence = an = a[n-1] + 3
12 is 75% of what
is means equals, of means multiply
12 = 75% * what
12 = .75 * what
divide each side by .75
12/.75 = .75 * what /.75
16 = what
12 is 75 percent of 16
the answer is 16
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recall again, sin²(θ) + cos²(θ) = 1.
Answer:
(2,4)
Step-by-step explanation:
We have the system:
y=x+2
y=3x-2.
This is already setup for substitution.
I'm going to replace my first y with what the second y equals.
That is, I'm going to write 3x-2=x+2.
Time to solve the following for x:
3x-2=x+2
Subtract x on both sides:
2x-2= 2
Add 2 on both sides:
2x. = 4
Divide both sides by 2:
x. = 2
Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.
So we y=x+2 with x=2 which means y=2+2=4.
So the solution, the intersection, is (2,4).