All categories

3 years ago

Triangle ABC and triangle DEF are similar.

Mathematics

1 answer:

cestrela7 [59]3 years ago

4 0

Answer:

x=25

Step-by-step explanation:

Since both triangles are similar, you can set them up as a proportional problem

x/20=32/(8+20+12) Solve for x, you can so cross multiply method.

32x=800

x=25

You might be interested in

A recipe calls for 8 cups of flour for every 4 cups of sugar. How many cups of sugar are used for each cup of flour?

ANEK [815]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help! I will give brainlest answer

Sidana [21]

Connect the bdc letters together.

8 0

4 years ago

Read 2 more answers

PLS HELP I GIVE BRAINLIEST

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

relative speed is calculated by the difference of the one with respect to the other

let car be 70 mph

and lorry be 50 mph../

relative speed of car with respect to lorry = 70-50 = 20 mph

this is ur answer

3 0

3 years ago

Step1. Formulate two real-life problems involving system of linear inequalities in

pav-90 [236]

╱╱▏┈┈╱╱╱╱▏╱╱▏

▇╱▏┈┈▇▇▇╱▏▇╱▏

▇╱▏▁┈▇╱▇╱▏▇╱▏▁

▇╱╱╱▏▇╱▇╱▏▇╱╱╱

▇▇▇╱┈▇▇▇╱┈▇▇▇╱

4 0

3 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

3 years ago