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Oksana_A [137]
3 years ago
14

Hurry please :3 thank you

Mathematics
2 answers:
Marrrta [24]3 years ago
6 0

Answer:

10

High Hopes

                        Barry-

Vikentia [17]3 years ago
3 0

Answer:

10

Step-by-step explanation:

I believe the answer is ten! I hope this helps you!

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(3+2a)² alguien sabe la respuesta?
asambeis [7]

Answer:

3(3+2a)+2a(3+2a)

9+6a+6a+4a^2

9+12a+4a^2

ANS 4a^2+12a+9

6 0
2 years ago
G(x)=-4+7 rate of change
Ratling [72]
What exactly are you trying to find but I tried to do the problem and I got 3
6 0
3 years ago
Find the velocity v(t)v(t) and speed ∥v(t)∥∥v(t)∥ of a particle whose motion is described by x=6t3−9t2,y=3,z=2t2−4t+2
Nesterboy [21]
Let \mathbf p(t)=(x(t),y(t),z(t)) denote the particle's position. Then its velocity is given by

\mathbf v(t)=\dfrac{\mathrm d\mathbf p}{\mathrm dt}=(x'(t),y'(t),z'(t))
\mathbf v(t)=(18t^2-18t,0,4t-4)

The speed is then given by the absolute value/magnitude/norm of the velocity function,

\|\mathbf v(t)\|=\sqrt{(18t^2-18t)^2+(4t-4)^2}
7 0
3 years ago
20% off the regular price of $32.50
yuradex [85]
You multiply the original price by .20
7 0
3 years ago
Tim is playing a game. His score in round 1 is 1.7 points, in round 2 is 5.1 points, in round 3 is 15.3 points, and it continues
tatiyna

The recursive definition for the geometric sequence is given as follows:

a_n = 3a_{n-1}, a_1 = 1.7

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

The recursive definition of a geometric sequence is given by:

a_n = qa_{n-1}

In this problem, we have that the first term and the common ratio are given, respectively, by:

a_1 = 1.7, q = \frac{15.3}{5.1} = \frac{5.1}{1.7} = 3.

Hence the recursive definition is given by:

a_n = 3a_{n-1}, a_1 = 1.7

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

4 0
2 years ago
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