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denpristay [2]
3 years ago
10

9. Stephanie had some candy to give to her four children. She first

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Answer:

36

Step-by-step explanation:

Create an equation : 12 for how many pieces Stephanie took, 4 for how many children she has and 6 for how many pieces each child got:

12+ (6*4) = x

Solve:

12+24 = 36

Nimfa-mama [501]3 years ago
4 0

Answer: 36 pieces

Step-by-step explanation:

We know she took 12 pieces and her four children each received 6 pieces.

12 + 4 (6) = p

12 + 24 = 36

p = 36

She started with 36 pieces.

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The first four terms of an arithmetic sequence are -11,-5,1,7. what is the equation for an
mr_godi [17]

Answer:

y = 6x - 11

Step-by-step explanation:

An arithmetic sequence is a linear function. This means it steadily increases or decreases through addition/subtraction by a constant amount. Here the sequence grows by adding 6 each time.

-11 + 6 = -5

-5 + 6 = 1

1 + 6 = 7

etc....

Since this is linear, its equation has the form y = mx + b where m is the slope and b is the y-intercept. The slope is m = 6 and b = -11.

y = 6x - 11

7 0
3 years ago
1) Jessica charges $8 an hour for babysitting
nordsb [41]
A. The independent variable is time, as time is manipulating the value of her salary.

b. The dependent variable is her cost because what she charges for babysitting depends on how long she works.

c. y = 8x
y = how much she charges for this job
8 = the amount she charges per hour
x = number of hours babysat
6 0
3 years ago
What is 2 5/6 + 7/4 <br> A. 2 2/5<br> B. 3 1/5<br> C. 3 4/5<br> D. 4 7/12
Mazyrski [523]

Answer:

D

Step-by-step explanation:

2 5/6=2 10/12

7/4=1 3/4= 1 9/12

2 10/12+1 9/12= 4 7/12

you can just change the denominators to the same which is 12. Hope you appreciate it!

7 0
2 years ago
Write a sentence to represent the equation 4m = -8.
Fittoniya [83]

Four times a number is equal to negative eight.

4 0
2 years ago
Read 2 more answers
Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,
qaws [65]
\dfrac{\partial f}{\partial x}=y^2z+2xz^2
f(x,y,z)=xy^2z+x^2z^2+g(y,z)

\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz
\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z
\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0

\implies f(x,y,z)=xy^2z+x^2z^2+C
8 0
3 years ago
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