The anticipated time when he will appear again is 5:17 pm
The given parameters;
your speed,
= 3 m/s
the runner's speed,
= 14 m/s
the diameter of the lake, d = 2 miles = 3218.69 meters
- Let the anticipated time when he will appear again = t
The circumference of the lake is calculated as;

Apply concept of relative velocity to determine the time, in which he will appear again.
By the time he appears again;
the distance you moved + distance he moved = circumference of the circle


Thus, the anticipated time when he will appear again is 5:17 pm
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