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Delvig [45]
3 years ago
5

A ball is fired from a cannon from the top of a cliff as shown below. Which of the paths 1 - 5 would the cannonball most closely

follow?

Physics
2 answers:
vladimir1956 [14]3 years ago
6 0

When a ball is fired from a cannon horizontally, then it will follow the projectile path. So the cannonball most closely follow the path number 2.

You can also see in the attachment my drawing.

----

<h3>Which of the paths below would the puck most closely follow after receiving the kick?</h3>

<u>The answer is B.</u>

C, D and E describe curved paths which indicate accelerated motion over time. Since the kick was “swift” the force on the puck, and therefore its acceleration was instantaneous. The horizontal motion in A is cancelled out, which would imply a force to stop it in the horizontal direction, which did not occur.

<h3>Vector A is directed northward and vector B is directed eastward. Which of the following vector addition diagrams best represent the addition of vectors A and B and the subsequent resultant?</h3>

The graphical representation of A directed northward, and B directed eastward. <u>The vector representing a b most closely</u> is by adding the tail of one of the vectors to the head of the other vector.

Looking our options the answer will be (E).

<h3>Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single story building at the same instant of time. The time it takes the balls to reach the ground below will be:</h3>

The answer is about the same for both balls. For more explanations go to brainly.com/question/14173803

<h3>A boy throws a steel ball straight up. Consider the motion of the ball only after it has left the boy's hand but before it touches the ground, and assume that forces exerted by the air are negligible. For these conditions, the force(s) acting on the ball is (are):</h3>

The answer is "an almost constant downward force of gravity only." For more explanations, go to brainly.com/question/19578722

<h3>An elevator is being lifted up an elevator shaft at a constant speed by a steel cable as shown in the figure below. All frictional effects are negligible. In this situation, forces on the elevator are such that:</h3><h3>(A) the upward force by the cable is greater than the downward force of gravity.</h3><h3>(B) the upward force by the cable is equal to the downward force of gravity.</h3><h3>(C) the upward force by the cable is smaller than the downward force of gravity.</h3><h3>(D) the upward force by the cable is greater than the sum of the downward force of gravity and a downward force due to the air.</h3><h3>(E) none of the above. (The elevator goes up because the cable is being shortened, not because an upward force is exerted on the elevator by the cable).</h3>

The answer is (B). Remember about constant speed.

<h3>Which path in the figure at right would the ball most closely follow after it exits the channel at "r" and moves across the frictionless table top?</h3><h3>a. Path 1</h3><h3>b. Path 2</h3><h3>c. Path 3</h3><h3>d. Path 4</h3><h3>e. Path 5</h3><h3 />

The answer is (B). Velocity in a circular motion is tangential. That's why it will remain in the same direction of tangent. It closely moves in straight line path so it follows the path B. Velocity

<h3>A student throws a ball to a friend which of the following causes the ball to fall downward</h3>

The answer is Gravity. Gravity caused the ball to fall.

<h3>The figure below shows a boy swinging on a rope, starting at a point higher than A. Consider the following distinct forces:</h3><h3>1. A downward force of gravity.</h3><h3>2. A force exerted by the rope pointing from A to O.</h3><h3>3. A force in the direction of the boy’s motion.</h3><h3>4. A force pointing from O to A.</h3><h3>Which of the above forces is (are) acting on the boy when he is at position A?</h3><h3>(a) 1 only.</h3><h3>(b) 1 and 2.</h3><h3>(c) 1 and 3.</h3><h3>(d) 1, 2, and 3.</h3><h3>(e) 1, 3, and 4.</h3>

The answer is A. Only the force of gravity and the tension force from the swing act on the person.

Lina20 [59]3 years ago
5 0

When the cannonball is fired from the cliff, it will most closely follow the path 2.

<h3>What is a projectile motion?</h3>

This a type of motion in which the projectile experiences the influence of Earth gravity causing the projectile take a parabolic  or curved trajectory.

The cannonball is an example of a projectile and its path of motion will be parabolic or curved.

From the given graph;

  • The path 1 is a linear path
  • The path is a parabolic path
  • The path 3-5 is linear and curved

Thus, when the cannonball is fired from the cliff, it will most closely follow the path 2.

Learn more about trajectory of a projectile here: brainly.com/question/1912408

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Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli
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Answer:

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

Explanation:

Given:

Mass of  Glidding Cart = m₁ = 2 kg

Mass of Stationary Cart = m₂ = 5 kg

Initial velocity of Glidding Cart = u₁ = 14 m/s

Initial velocity of Stationary Cart = u₂ = 0 m/s

To Find:

Final velocity of the coupled carts after the collision = v_{f}=?

Solution:

Law of Conservation of Momentum:

For a collision occurring between two objects in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

It is denoted by "p" and given by

Momentum = p = mass × velocity

Hence by law of Conservation of Momentum we hame

Momentum before collision = Momentum after collision

Here after collision both are stuck together so both will have same final velocity,

m_{1}\times u_{1}+m_{2}\times u_{2}=(m_{1}+m_{2})\times v_{f}

Substituting the values we get

2\times 14 + 5\times 0 =(2+5)\times v_{f}

v_{f}=\dfrac{28}{7}=4\ m/s

Therefore,

Final velocity of the coupled carts after the collision is

v_{f}=4\ m/s

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Answer:

False

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  • Only Promethium in this group are radioactive in nature.
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