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Delvig [45]
2 years ago
5

A ball is fired from a cannon from the top of a cliff as shown below. Which of the paths 1 - 5 would the cannonball most closely

follow?

Physics
2 answers:
vladimir1956 [14]2 years ago
6 0

When a ball is fired from a cannon horizontally, then it will follow the projectile path. So the cannonball most closely follow the path number 2.

You can also see in the attachment my drawing.

----

<h3>Which of the paths below would the puck most closely follow after receiving the kick?</h3>

<u>The answer is B.</u>

C, D and E describe curved paths which indicate accelerated motion over time. Since the kick was “swift” the force on the puck, and therefore its acceleration was instantaneous. The horizontal motion in A is cancelled out, which would imply a force to stop it in the horizontal direction, which did not occur.

<h3>Vector A is directed northward and vector B is directed eastward. Which of the following vector addition diagrams best represent the addition of vectors A and B and the subsequent resultant?</h3>

The graphical representation of A directed northward, and B directed eastward. <u>The vector representing a b most closely</u> is by adding the tail of one of the vectors to the head of the other vector.

Looking our options the answer will be (E).

<h3>Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single story building at the same instant of time. The time it takes the balls to reach the ground below will be:</h3>

The answer is about the same for both balls. For more explanations go to brainly.com/question/14173803

<h3>A boy throws a steel ball straight up. Consider the motion of the ball only after it has left the boy's hand but before it touches the ground, and assume that forces exerted by the air are negligible. For these conditions, the force(s) acting on the ball is (are):</h3>

The answer is "an almost constant downward force of gravity only." For more explanations, go to brainly.com/question/19578722

<h3>An elevator is being lifted up an elevator shaft at a constant speed by a steel cable as shown in the figure below. All frictional effects are negligible. In this situation, forces on the elevator are such that:</h3><h3>(A) the upward force by the cable is greater than the downward force of gravity.</h3><h3>(B) the upward force by the cable is equal to the downward force of gravity.</h3><h3>(C) the upward force by the cable is smaller than the downward force of gravity.</h3><h3>(D) the upward force by the cable is greater than the sum of the downward force of gravity and a downward force due to the air.</h3><h3>(E) none of the above. (The elevator goes up because the cable is being shortened, not because an upward force is exerted on the elevator by the cable).</h3>

The answer is (B). Remember about constant speed.

<h3>Which path in the figure at right would the ball most closely follow after it exits the channel at "r" and moves across the frictionless table top?</h3><h3>a. Path 1</h3><h3>b. Path 2</h3><h3>c. Path 3</h3><h3>d. Path 4</h3><h3>e. Path 5</h3><h3 />

The answer is (B). Velocity in a circular motion is tangential. That's why it will remain in the same direction of tangent. It closely moves in straight line path so it follows the path B. Velocity

<h3>A student throws a ball to a friend which of the following causes the ball to fall downward</h3>

The answer is Gravity. Gravity caused the ball to fall.

<h3>The figure below shows a boy swinging on a rope, starting at a point higher than A. Consider the following distinct forces:</h3><h3>1. A downward force of gravity.</h3><h3>2. A force exerted by the rope pointing from A to O.</h3><h3>3. A force in the direction of the boy’s motion.</h3><h3>4. A force pointing from O to A.</h3><h3>Which of the above forces is (are) acting on the boy when he is at position A?</h3><h3>(a) 1 only.</h3><h3>(b) 1 and 2.</h3><h3>(c) 1 and 3.</h3><h3>(d) 1, 2, and 3.</h3><h3>(e) 1, 3, and 4.</h3>

The answer is A. Only the force of gravity and the tension force from the swing act on the person.

Lina20 [59]2 years ago
5 0

When the cannonball is fired from the cliff, it will most closely follow the path 2.

<h3>What is a projectile motion?</h3>

This a type of motion in which the projectile experiences the influence of Earth gravity causing the projectile take a parabolic  or curved trajectory.

The cannonball is an example of a projectile and its path of motion will be parabolic or curved.

From the given graph;

  • The path 1 is a linear path
  • The path is a parabolic path
  • The path 3-5 is linear and curved

Thus, when the cannonball is fired from the cliff, it will most closely follow the path 2.

Learn more about trajectory of a projectile here: brainly.com/question/1912408

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swat32
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6 0
2 years ago
What what is the direction of an object’s acceleration if it is being pulled upward by a rope at a constant speed?
Arada [10]

Answer:

the direction is towards upward.i think.

7 0
3 years ago
a certain projetor uses a concave mirror for projecting an object's image on a screen .it produces on image that is 4 times bigg
IrinaK [193]

Answer:

f = 1 m

Explanation:

The magnification of the lens is given by the formula:

M = \frac{q}{p}

where,

M = Magnification = 4

q = image distance = 5 m

p = object distance = ?

Therefore,

4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m

Now using thin lens formula:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\

<u>f = 1 m</u>

6 0
2 years ago
The escape speed from the moon is much smaller than from earth. True or False
Lisa [10]

Answer:

True

The escape speed from the Moon is much smaller than from Earth.

Explanation:

The escape speed is defined as:

v_{e} = \sqrt{\frac{2GM}{r}}  (1)

Where G is the gravitational constant, M is the mass and r is the radius.

The mass of the Earth is 5.972x10^{24}kg and its radius is 6371000m

Then, replacing those values in equation 1 it is gotten.

v_{e} = \sqrt{\frac{(2)(6.67x10^{-11}N.m^{2}/kg^{2})(5.972x10^{24}kg)}{(6371000m)}}  

v_{e} = 11.18m/s

For the case of the Moon:

v_{e} = \sqrt{\frac{(2)(6.67x10^{-11}N.m^{2}/kg^{2})(7.347x10^{22}Kg)}{(1737000m)}}  

v_{e} = 2.38m/s

Hence, the escape speed from the Moon is much smaller than from Earth.

Since it has a smaller mass and smaller radius compared to that from the Earth.

4 0
3 years ago
What is the maximum angular momentum Lmax that an electron with principal quantum number n = 2 can have? Express your answer in
butalik [34]

Answer:

L_{max} = 1.414 ℏ

Given:

Principle quantum number, n = 2

Solution:

To calculate the maximum angular momentum, L_{max}, we have:

L_{max} = \sqrt {l(1 + l)}                              (1)

where,

l = azimuthal quantum number or angular momentum quantum number

Also,

n = 1 + l

2 = 1 + l

l = 1

Now,

Using the value of l = 1 in eqn (1), we get:

L_{max} = \sqrt {1(1 + 1)} = \sqrt 2

L_{max} = 1.414 ℏ

4 0
3 years ago
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