1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Delvig [45]
3 years ago
5

A ball is fired from a cannon from the top of a cliff as shown below. Which of the paths 1 - 5 would the cannonball most closely

follow?

Physics
2 answers:
vladimir1956 [14]3 years ago
6 0

When a ball is fired from a cannon horizontally, then it will follow the projectile path. So the cannonball most closely follow the path number 2.

You can also see in the attachment my drawing.

----

<h3>Which of the paths below would the puck most closely follow after receiving the kick?</h3>

<u>The answer is B.</u>

C, D and E describe curved paths which indicate accelerated motion over time. Since the kick was “swift” the force on the puck, and therefore its acceleration was instantaneous. The horizontal motion in A is cancelled out, which would imply a force to stop it in the horizontal direction, which did not occur.

<h3>Vector A is directed northward and vector B is directed eastward. Which of the following vector addition diagrams best represent the addition of vectors A and B and the subsequent resultant?</h3>

The graphical representation of A directed northward, and B directed eastward. <u>The vector representing a b most closely</u> is by adding the tail of one of the vectors to the head of the other vector.

Looking our options the answer will be (E).

<h3>Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single story building at the same instant of time. The time it takes the balls to reach the ground below will be:</h3>

The answer is about the same for both balls. For more explanations go to brainly.com/question/14173803

<h3>A boy throws a steel ball straight up. Consider the motion of the ball only after it has left the boy's hand but before it touches the ground, and assume that forces exerted by the air are negligible. For these conditions, the force(s) acting on the ball is (are):</h3>

The answer is "an almost constant downward force of gravity only." For more explanations, go to brainly.com/question/19578722

<h3>An elevator is being lifted up an elevator shaft at a constant speed by a steel cable as shown in the figure below. All frictional effects are negligible. In this situation, forces on the elevator are such that:</h3><h3>(A) the upward force by the cable is greater than the downward force of gravity.</h3><h3>(B) the upward force by the cable is equal to the downward force of gravity.</h3><h3>(C) the upward force by the cable is smaller than the downward force of gravity.</h3><h3>(D) the upward force by the cable is greater than the sum of the downward force of gravity and a downward force due to the air.</h3><h3>(E) none of the above. (The elevator goes up because the cable is being shortened, not because an upward force is exerted on the elevator by the cable).</h3>

The answer is (B). Remember about constant speed.

<h3>Which path in the figure at right would the ball most closely follow after it exits the channel at "r" and moves across the frictionless table top?</h3><h3>a. Path 1</h3><h3>b. Path 2</h3><h3>c. Path 3</h3><h3>d. Path 4</h3><h3>e. Path 5</h3><h3 />

The answer is (B). Velocity in a circular motion is tangential. That's why it will remain in the same direction of tangent. It closely moves in straight line path so it follows the path B. Velocity

<h3>A student throws a ball to a friend which of the following causes the ball to fall downward</h3>

The answer is Gravity. Gravity caused the ball to fall.

<h3>The figure below shows a boy swinging on a rope, starting at a point higher than A. Consider the following distinct forces:</h3><h3>1. A downward force of gravity.</h3><h3>2. A force exerted by the rope pointing from A to O.</h3><h3>3. A force in the direction of the boy’s motion.</h3><h3>4. A force pointing from O to A.</h3><h3>Which of the above forces is (are) acting on the boy when he is at position A?</h3><h3>(a) 1 only.</h3><h3>(b) 1 and 2.</h3><h3>(c) 1 and 3.</h3><h3>(d) 1, 2, and 3.</h3><h3>(e) 1, 3, and 4.</h3>

The answer is A. Only the force of gravity and the tension force from the swing act on the person.

Lina20 [59]3 years ago
5 0

When the cannonball is fired from the cliff, it will most closely follow the path 2.

<h3>What is a projectile motion?</h3>

This a type of motion in which the projectile experiences the influence of Earth gravity causing the projectile take a parabolic  or curved trajectory.

The cannonball is an example of a projectile and its path of motion will be parabolic or curved.

From the given graph;

  • The path 1 is a linear path
  • The path is a parabolic path
  • The path 3-5 is linear and curved

Thus, when the cannonball is fired from the cliff, it will most closely follow the path 2.

Learn more about trajectory of a projectile here: brainly.com/question/1912408

You might be interested in
If Judy walks 2 blocks north, 5 blocks west, and then 2 blocks south, what is her final
VladimirAG [237]

Answer: 2 blocks east if i'm not mistaken.

7 0
3 years ago
A trick shot archer shoots an arrow with a velocity of 30.0 m/s at an angle of 20.0 degrees with respect to the horizontal. An a
svlad2 [7]

Answer:

u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

the apple should be tossed after \Delta t=0.0173\ s

Explanation:

Given:

  • velocity of arrow in projectile, v=30\ m.s^{-1}
  • angle of projectile from the horizontal, \theta=20^{\circ}
  • distance of the point of tossing up of an apple, d=30\ m

<u>Now the horizontal component of velocity:</u>

v_x=v\ cos\ \theta

v_x=30\times cos\ 20^{\circ}

v_x=28.191\ m.s^{-1}

<u>The vertical component of the velocity:</u>

v_y=v.sin\ \theta

v_y=30\times sin\ 20^{\circ}

v_y=10.261\ m.s^{-1}

<u>Time taken by the projectile to travel the distance of 30 m:</u>

t=\frac{d}{v_x}

t=\frac{30}{28.191}

t=1.0642\ s

<u>Vertical position of the projectile at this time:</u>

h=v_y.t-\frac{1}{2}g.t^2

h=10.261\times 1.0642-\frac{1}{2} \times 9.8\times 1.0642^2

h=5.3701\ m

<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

v'^2=u'^2-2g.h

0^2=u'^2-2\times 9.8\times 5.3701

u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

v'=u'-g.t'

0=10.259-9.8\times t'

t'=1.0469\ s

<u>We observe that </u>t>t'<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

\Delta t=t-t'

\Delta t=1.0642-1.0469

\Delta t=0.0173\ s

8 0
4 years ago
A 68 kg rock climbers 320 m above the ground the sun is down or up at 1.5 m/s using the ground as a reference point determine th
pochemuha

Answer:

213.5 kJ

Explanation:

Mechanical energy= kinetic energy + potential energy= KE+PE=0.5mv^{2}+mgh= m(0.5v^{2}+gh) where m is the mass of rock climber, v is the velocity, g is acceleration due to gravity and h is the height.

By substitution where 68 Kg is m, 320 m is h, 1.5 m/s is v and 9.81 is g then

Mechanical energy=68(0.5\times 1.5^{2}+9.81\times 320)=213542.1 J\approx 213.5 kJ

8 0
3 years ago
PLEASE I NEED HELP!!
Bond [772]

Answer:

may be 5 m is the answer of this question

4 0
2 years ago
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potent
charle [14.2K]

Answer:

A

Explanation:

Given that a stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy. (use 9 - 10 m/s)

O at the moment of impact

2 seconds after the stone is released after the stone has fallen 40 m

when the stone is moving at 20 m/s

At the top of the hill, the P.E = mgh

P.E = 10 × 80 × m

P.E = 800m

At the moment of impact, K.E = 1/2mv^2

K.E = 1/2 × 40^2 × m

K.E = 1/2 × 1600 × m

K.E = 800m

Since both P.E and K.E are the same, we can therefore conclude that the stone's potential energy with respect to the ground is equal to its kinetic energy at the moment of impact.

The correct answer is option A.

4 0
3 years ago
Other questions:
  • Which types of materials have a molecular structure that makes them good conductors? Explain how understanding this relationship
    9·2 answers
  • Prehistory can be described as _____.
    8·1 answer
  • The production of an electric current by a changing magnetic field is known as
    7·2 answers
  • A resource, such as oil, that cannot regenerate in a reasonable amount of time is called
    7·2 answers
  • What journey did life take to generate biodiversity that exists today ?
    5·1 answer
  • A moving object has a kinetic energy of 20 J. if it’s velocity doubles, it’s kinetic energy would be
    7·1 answer
  • There are two identical, positively charged conducting spheres fixed in space. The spheres are 44.0 cm apart (center to center)
    7·1 answer
  • 45 j of 100 j of was used to turn on the television what is the percentage of energy used
    8·2 answers
  • When is the ideal time to take a resting heart rate? O A. After exercise OB. After a meal OC. Hirst thing in the morning D. Befo
    5·1 answer
  • Contrast the behavior of a water wave that travel by a stone barrier to a sound wave that travels through a door
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!