Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer:
9;10
Step-by-step explanation:
What we can first do is make them into one double sided inequality and then interpret it from there.
After combining them we get: 7<x<12
This means that any number between 7 and 12 can be picked.
Keep in mind, this means that 7 and 12 cannot be picked, they have to be in between.
Therefore, we get our aswers of 9 and 10!
Answer:
1/38
Step-by-step explanation:
Given :
Probability = required outcome / Total possible outcomes
Total possible outcomes = total Numbe rod sections = 38
Required outcome = number of 1's on the entire section = 1
Hence, the probability of spinning a one equals :
P(spinning a 1) = 1 / 38
