1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fenix001 [56]
3 years ago
15

Determine the displacement of end A with respect to end D if the diameters of each segment are dAB = 0.85 in ., dBC = 1.1 in .,

and dCD = 0.45 in . Take Ecu= 18(103)ksi.

Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer / Step-by-step explanation:

It should be noted that the question is incomplete due to the fact that the diagram has not been provided. However, the diagram has been complementing the question has been provided below.

To solve the question in the narrative, we recall the equation used in solving for displacement:

Thus, δₙₐ = Σ pL/AE

Where:

P is applied axial force.

E is the young's modulus of elasticity.

A is the area of cross-section.

L is length of the bar

Therefore,  -8 (80) ÷ π/4 ( 0.85)² (18) (10³) +  2(150) ÷ π/4 (1.1)² (18) (10³) + 6(100) ÷ π/4 (0.45)² (18) (10³)

Solving further,

we have,

-8 (80) ÷ 0.7853( 0.85)² (18) (10³) + 2(150) ÷ 0.7853(1.1)² (18) (10³) + 6(100) ÷ 0.7853 (0.45)² (18) (10³)

= -640÷ 0.7853( 0.85)² (18) (10³) + 300 ÷ 0.7853(1.1)² (18) (10³) + 600 ÷ 0.7853 (0.45)² (18) (10³)

Solving further, we arrive at 0.111 in answer.

The positive sign indicates that end A moves away from end D.

 

You might be interested in
Jackson used the process of completing the square to solve the equation 2x2−12x=−6.
Nikolay [14]

Answer:

x=3-\sqrt{6},x=3+\sqrt{6}

Step-by-step explanation:

we are given equation as

2x^2-12x=-6

Since, we have to solve it by using complete square

so, firstly we will complete square

and then we can solve for x

step-1:

Factor 2 from both sides

2(x^2-6x)=-3\times 2

step-2:

Simplify it

x^2-6x=-3

step-3:

Add both sides 3^2

x^2-6x+3^2=-3+3^2

now, we can complete square

(x-3)^2=6

step-4:

Take sqrt both sides

(x-3)=-\sqrt{6},(x-3)=\sqrt{6}

step-5:

Add both sides by 3

we get

x=3-\sqrt{6},x=3+\sqrt{6}


3 0
3 years ago
What is the solution for the equation 5/3b^3-2b^2-5=2/b^3-2
PilotLPTM [1.2K]
I looked it up and it said it was c 
7 0
3 years ago
Read 2 more answers
Students conducted a survey to see which cola was preferred most. People preferred cola A to cola B by a ratio of 9:7. If 108 pe
tigry1 [53]

Answer:

c:84

Step-by-step explanation:

set your equasion to 9/7 = 108/x .solve the equasion and you get 84 for x

4 0
3 years ago
(a) If G is a finite group of even order, show that there must be an element a = e, such that a−1 = a (b) Give an example to sho
Dahasolnce [82]

Answer:

See proof below

Step-by-step explanation:

First, notice that if a≠e and a^-1=a, then a²=e (this is an equivalent way of formulating the problem).

a) Since G has even order, |G|=2n for some positive number n. Let e be the identity element of G. Then A=G\{e} is a set with 2n-1 elements.

Now reason inductively with A by "pairing elements with its inverses":

List A as A={a1,a2,a3,...,a_(2n-1)}. If a1²=e, then we have proved the theorem.

If not, then a1^(-1)≠a1, hence a1^(-1)=aj for some j>1 (it is impossible that a^(-1)=e, since e is the only element in G such that e^(-1)=e). Reorder the elements of A in such a way that a2=a^(-1), therefore a2^(-1)=a1.

Now consider the set A\{a1,a2}={a3,a4,...,a_(2n-1)}. If a3²=e, then we have proved the theorem.

If not, then a3^(-1)≠a1, hence we can reorder this set to get a3^(-1)=a4 (it is impossible that a^(-1)∈{e,a1,a2} because inverses are unique and e^(-1)=e, a1^(-1)=a2, a2^(-1)=a1 and a3∉{e,a1,a2}.

Again, consider A\{a1,a2,a3,a4}={a5,a6,...,a_(2n-1)} and repeat this reasoning. In the k-th step, either we proved the theorem, or obtained that a_(2k-1)^(-1)=a_(2k)

After n-1 steps, if the theorem has not been proven, we end up with the set A\{a1,a2,a3,a4,...,a_(2n-3), a_(2n-2)}={a_(2n-1)}. By process of elimination, we must have that a_(2n-1)^(-1)=a_(2n-1), since this last element was not chosen from any of the previous inverses. Additionally, a_(2n1)≠e by construction. Hence, in any case, the statement holds true.

b) Consider the group (Z3,+), the integers modulo 3 with addition modulo 3. (Z3={0,1,2}). Z3 has odd order, namely |Z3|=3.

Here, e=0. Note that 1²=1+1=2≠e, and 2²=2+2=4mod3=1≠e. Therefore the conclusion of part a) does not hold

7 0
3 years ago
At Tanika's school, 3 people are chosen in the first round. Each of those people chooses 3 people in the second round, and so on
notka56 [123]
96 people. With every round, the number of people doubles. 3 turns into 6, which turns into 12, which turns into 24, which turns into 48, which turns into 96. The process is repeated only 5 times, but keep in mind when 3 people are chosen, it ends the first round. Hope this helps!!!

-Anonymous

7 0
2 years ago
Read 2 more answers
Other questions:
  • The mean of the temperatures in the chart is 24° with a standard deviation of 4°. which temperature is within one standard devia
    8·2 answers
  • Trsanslate to an algebraic expression. EASY 35 POINTS
    5·2 answers
  • A scale on a hiking map shows that 333 inches represents 1.251.251, point, 25 miles.
    12·2 answers
  • Find the value of C in a triangle where a = 6, b = 8, and c = 12.
    13·1 answer
  • What is the range of the following function?
    10·1 answer
  • By what fraction would you multiply 8 1/2 so that the product is about 5
    5·2 answers
  • If you have 3x + y = 9 write it in slope intercept form... what is the slope, y intercept?
    13·1 answer
  • 39.96÷6 with explanation​
    15·2 answers
  • Mark takes out a $238,000 mortgage for 30 years. Instead of paying his monthly payment of $1,220.09, he decided to pay $1,420.09
    5·1 answer
  • HELP PLEASE ILL GIVE YOU BRAINLEST IF U GIVE ME THE CORRECT ANSWER FOR THE QUESTION IN THE PIC
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!