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AysviL [449]
3 years ago
9

The length of a bed would be about

Mathematics
2 answers:
stepan [7]3 years ago
5 0

Answer:

2 yards.

Step-by-step explanation:

We know that a length of a bed is DEFINITELY not 2 miles, and it isn't 2 inches either, because they're both too big and too small. However, 2 feet is also pretty small, too, because 2 feet is about the size of a crib. So what's left is 2 yards, so a bed is about 2 yards.

uysha [10]3 years ago
4 0

Answer:

2 yards

Step-by-step explanation:

The question is asking what the length of a bed would be.

To answer this question, it's basically common sense, how long is a bed usually, it would be about 5 to 10 feet, big enough to fit a human with no uncomfortability.

So with this info, we can scratch D and B. As for A and C, let's convert them into feet.

1 yard equals 3 feet, meaning two yards would be 6 feet.

1 mile is 5280 feet, this is obviously wrong.

A is our answer.

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Trevor spent $27 and now has no money left. What did he have before his purchase
Sav [38]

Answer:$27

Step-by-step explanation:

x-27=0

0+27=27

27-27=0

8 0
3 years ago
Do you know the inequality? Please explain and show answer :)
DerKrebs [107]
If u have a open circle, then the inequality has no equal sign. But if it is a closed circle, the inequality has an equal sign.
Shading to the left means " less then " .
Shading to the right means " greater then " .

(1) u have an open circle on -7 with shading to the left....
     x < -7

(2) u have a closed circle on 4.5 with shading to the left....
    x < = 4.5 (thats less then or equal)

(3) u have an open circle on -5 with shading to the right...
     x > -5

(4) u have an open circle on 1.5 with shading to the right...
     x > 1.5


4 0
3 years ago
Which of the following numbers represents the fraction 8/9 to the nearest percent?
jekas [21]
The number that presents 8/9 to the nearest percent is .89.
6 0
2 years ago
0.18(y-9)+0.06y=0.04y-0.9
Ksju [112]
Simplify both sides then isolate the variable and it gives you y=3.6
7 0
3 years ago
Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc
DerKrebs [107]

we are given

differential equation as

y'''-9y''+20y'=0

we are given

y=e^{rx}

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

y'=re^{rx}

Second derivative is

y''=r*re^{rx}

y''=r^2e^{rx}

Third derivative is

y'''=r^2*re^{rx}

y'''=r^3e^{rx}

now, we can plug these values into differential equation

and we get

r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0

now, we can factor out common terms

e^{rx}(r^3 -9r^2 +20r)=0

we can move that term on right side

(r^3 -9r^2 +20r)=0

now, we can factor out

r(r^2 -9r +20)=0

r(r-5)(r-4)=0

now, we can set them equal

r=0

r-5=0

r=5

r-4=0

r=4

so, we will get

r=0,4,5...............Answer

4 0
3 years ago
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