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AysviL [449]
3 years ago
9

The length of a bed would be about

Mathematics
2 answers:
stepan [7]3 years ago
5 0

Answer:

2 yards.

Step-by-step explanation:

We know that a length of a bed is DEFINITELY not 2 miles, and it isn't 2 inches either, because they're both too big and too small. However, 2 feet is also pretty small, too, because 2 feet is about the size of a crib. So what's left is 2 yards, so a bed is about 2 yards.

uysha [10]3 years ago
4 0

Answer:

2 yards

Step-by-step explanation:

The question is asking what the length of a bed would be.

To answer this question, it's basically common sense, how long is a bed usually, it would be about 5 to 10 feet, big enough to fit a human with no uncomfortability.

So with this info, we can scratch D and B. As for A and C, let's convert them into feet.

1 yard equals 3 feet, meaning two yards would be 6 feet.

1 mile is 5280 feet, this is obviously wrong.

A is our answer.

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Step-by-step explanation:

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BlackZzzverrR [31]

Answer:

27/8

Step-by-step explanation:

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Solve the equation below:<br> X+2/3x = 4/x
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4 0
3 years ago
1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
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