F(x)=x^5 + 5*x^4 - 5*x^3 - 25*x^2 + 4*x + 20
By examining the coefficients of the polynomial, we find that
1+5-5-25+4+20=0 => (x-1) is a factor
Now, reverse the sign of coefficients of odd powers,
-1+5+5-25-4+20=0 => (x+1) is a factor
By the rational roots theorem, we can continue to try x=2, or factor x-2=0
2^5+5(2^4)-5(2^3)-25(2^2)+4(2)+20=0
and similarly f(-2)=0
So we have found four of the 5 real roots.
The remainder can be found by synthetic division as x=-5
Answer: The real roots of the given polynomial are: {-5,-2,-1.1.2}
105 = 67 + x
x = 105 - 67
x = 38
So 12x 8+96 and you do 12 time 8 because x=12 and then 2x2 because y+4 and times by 2 because there is a 2 in front and that equals 8 and then 8x2 because z is 2 and add both sides =112
answer
112
Answer:
x=11
Step-by-step explanation:
These are alternate interior angles. Alternate interior angles are equal when the lines are parallel
6x =2x+44
Subtract 2x from each side
6x-2x =2x+44-2x
4x =44
Divide each side by 4
4x/4 = 44/4
x = 11
