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Nutka1998 [239]
3 years ago
14

M_VSR = Help meeeeeeeee

Mathematics
1 answer:
Nata [24]3 years ago
6 0

Answer:

80 degrees

Step-by-step explanation:

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Pls helppp me this is very very urgent
Nat2105 [25]

Answer:

1. 5040

2. 20

Step-by-step explanation:

1. using the formula for permutation

nPr=n!/(n-r)!

10P4 = 10!/(10-4)!

=10*9*8*7*6!/6!

then we are left with

=10*9*8*7

=5040

2.using the formula for combination

nCr=n!/(n-r)!r!

6C3=6!/(6-3)!3!

=6*5*4*3!/3!3!

=6*5*4/3*2*1

=20

4 0
3 years ago
Find the prime factorization of 50 using exponents
Elden [556K]
Five squared with the little two and 2 because 5 Times 10 is 50 and five is prime so then from 10 and you get five and two and both five and two are prime
5 0
3 years ago
Find the y-intercept of the line on the graph.<br>​
Darya [45]

Answer:

The y-intercept is the place where the line meets the y-axis

Step-by-step explanation:

7 0
2 years ago
(Use the Distributive Property to find an equivalent expression)<br> 2(3x-7y) = ?
IRINA_888 [86]

Answer:

(7y-3x)2

Step-by-step explanation:

It's the same thing but backwards

I hope this helps

6 0
2 years ago
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
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