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Harrizon [31]
3 years ago
10

Given a group of 17 people in a party, we consider the number of times a person shakes hand with someone else. Show that there i

s always two people who shake hands with the same total number of people.
Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that there is a group of 17 people in a party.  There takes place a number of hand shakes between them.

To show that there is always two people who shake hands with the same total number of people.

If possible let each person did a different number of handshake.

We know that since there are 17 people, there cannot be more than 16 hand shakes for any one in the group.

Hence if different hand shakes must be 0,1,2...16

Consider the last person having 16 hand shakes. He has shaken hand with each other person in the group thus making it clear that no one could have done 0 hand shakes.   Since we get a contradiction, our assumption was wrong. That is, there is always two people who shake hands with the same total number of people.

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10. For the equation 3x – 4 = 8, which
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Answer:

x  = 4

Step-by-step explanation:

We can find the answer to this by solving the equation:

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A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage
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We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

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We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

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This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

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For grade C:

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For grade D:

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