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Strike441 [17]
3 years ago
12

In a school with 400 students, a random sample of 40 students were asked which fruit is their favorite. Their responses are show

n below.
Apple - 10
Banana - 12
Peach - 8
Pear - 6
Strawberries - 4

Using proportional reasoning, about how many students in the school would you expect to select an pear as their favorite fruit?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

60

Step-by-step explanation:

divide 400 by 40 you get the answer 10

now multiply 6 by 10 you get the answer 60 thats is the total pear fruit

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Reese read twice as many pages Saturday than she read Sunday. If she read a total of 78 pages over the weekend, how many pages d
eimsori [14]

Given:

Reese read twice as many pages Saturday than she read Sunday.

She read a total of 78 pages over the weekend.

To find:

The number of pages she read on Sunday.

Solution:

Let x be the number of pages she read on Sunday.

Reese read twice as many pages Saturday than she read Sunday. So, the number of pager she read on Saturday is 2x.

Total number of page she read over the weekend is:

Total=x+2x

Total=3x

She read a total of 78 pages over the weekend.

3x=78

x=\dfrac{78}{3}

x=26

Therefore, Reese read 26 pages on Sunday.

3 0
2 years ago
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
2 years ago
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