Answer:75%
Explanation:
First, the balanced reaction equation must be written out clearly as a guide to solving the problem. The molar masses of H3PO4 and K3PO4 are then calculated as they will be consistently required in solving the problem. The theoretical yield is obtained from the amount of H3PO4 reacted. Since 1 mole of H3PO4 yields 1 mole of K3PO4, 0.05 moles of H3PO4 yields 0.05 moles of K3PO4. The mass of K3PO4 is produced is then the product of 0.05 and it molar mass hence the theoretical yield. The % yield is calculated as shown.
Answer:
12 g
Explanation:
We want to prepare 1 L of a 0.15 M NaOH solution. The moles of NaOH required are:
0.15 mol/L × 1 L = 0.15 mol
The molar mass of NaOH is 40.00 g/mol. The mass corresponding to 0.15 mol is:
0.15 mol × (40.00 g/mol) = 6.0 g
The starting solution is 50% by weight. The mass of solution that contains 6.0 g of NaOH is:
6.0 g NaOH × (100 g solution/50 g NaOH) = 12 g solution
Para and ortho is actually indicating different name structure of mixture. So if structure is different then boiling/distill/melt temprature will be also different.