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Maksim231197 [3]
3 years ago
14

If a 325 mL container of He gas with apressure of 0.8 atm increases its pressure to 1.5 atm, what is the resulting volume of the

container?
Chemistry
1 answer:
Shalnov [3]3 years ago
8 0
It’s still the same don’t let it get to i
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Which statement identifies the element arsenic ?
crimeas [40]

El arsénico puede provocar cáncer en pulmón y piel, e inclusive puede causar otros tipos de cánceres. Se observa una mayor fuerza de asociación entre la exposición crónica al arsénico y los cánceres de piel,El arsénico es un elemento químico de la tabla periódica que pertenece al grupo de los metaloides, también llamados semimetales, se puede encontrar de diversas formas, aunque raramente se encuentra en estado sólido. Se conoce desde la antigüedad y se reconoce como extremadamente tóxi ve

Símbolo: As

Configuración electrónica: [Ar] 3d104s24p3

Masa atómica: 74.9216 u ± 0.00002 u

Número atómico: 33

Electrones por nivel: 2, 8, 18, 5 (imagen)

Grupo, período, bloque: 15, 4, p.

6 0
4 years ago
Calculate the cost of 1.00 g of gold if the price gold is 655.00 per oz
Anna007 [38]

Answer:

22.96 $ per 1 g of gold

Explanation:

We know that 1 g is equal to 0.035 oz.

Now we formulate the following reasoning:

if         1 oz of gold have a value of 655 $

then    0.035 oz of gold have a value of X $

X = (0.035 × 655) / 1 = 22.96 $

3 0
3 years ago
Read 2 more answers
Which two factors are leading to an increased use of natural resources?
Ipatiy [6.2K]
What Drives Demand for Natural Resources?

Economic Growth. The rise of emerging markets has been the defining feature of the global economy this century.

Demographic Growth. The global population is growing and will reach 8.5 billion by 2030,
a 16.7% increase from 2015.

-Income Gains

-Environmental Change

-Technological Advancement

-Price Pressures
3 0
3 years ago
What determines the amount of energy in a chemical bonds?
kaheart [24]
The power of a bond, single, double and triple.
8 0
3 years ago
Please help!
koban [17]
A. 599 mg x 1g/1000mg x 1mole/174.24g = 0.003438 moles 
<span>b. 0.003438 moles x 1000 mmoles/mole = 3.438 moles </span>
<span>c. 0.003438 moles/0.741 L = 0.0046 M </span>
<span>d. [K+] = 2 x 0.0046 = 0.0092 M because each mole K2 SO4 yields 2 moles K+ </span>
<span>e. [SO42-] = 0.0046 M </span>
<span>f. 599 mg/0.741 L = 808.4 mg/L = 808 ppm </span>
<span>g. 0.599g/741 ml x 100 ml = 0.08 g/100 ml = 0.08% w/v </span>
<span>h. pK+ = -log [K+] = -log 0.0092 = 2.04 </span>
<span>i. pSO42- = -log [SO42-] = -log 0.0046 = 2.34</span>
4 0
3 years ago
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