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VLD [36.1K]
3 years ago
15

The specific heat of palladium is 0.239 J/g°C. How much heat (q) is released when a 10.0 g piece of platinum cools from 100.0°C

to 50.0°C?
Chemistry
1 answer:
Andrej [43]3 years ago
7 0

Answer:

119.5 J

Explanation:

First we <u>calculate the temperature difference</u>:

  • ΔT = 100 °C - 50 °C = 50 °C

Then we can <u>calculate the heat released</u> by using the following formula:

  • q = Cp * ΔT * m

Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.

We <u>input the data</u>:

  • q = 0.239 J/g°C * 50 °C * 10.0 g
  • q = 119.5 J
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Answer:

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Explanation:

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3 years ago
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A Lewis acid is an electron-pair acceptor.

Bronsted-Lowry bases are species that can accept a proton.

Arrhenius acid gives H^{+} ions.

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Bronsted-Lowry bases are species that can accept a proton due to a high-energy pair of electrons being present.

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4 0
2 years ago
Sam wants to demonstrate how water changes from a solid to a gas. He places ice in a pot on a stove. What variable is causing wa
olganol [36]
Hello,

The answer is option A "<span>the heat from the stove".

Reason:

The answer is option A because the variable the heat from the stove is causing the ice to change into water. Its not option B because thats not in the procedures. Its not option C because it is not a variable. Its also not D because thats also not a variable.

If you need anymore help feel free to ask me!

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Answer:

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