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VLD [36.1K]
3 years ago
15

The specific heat of palladium is 0.239 J/g°C. How much heat (q) is released when a 10.0 g piece of platinum cools from 100.0°C

to 50.0°C?
Chemistry
1 answer:
Andrej [43]3 years ago
7 0

Answer:

119.5 J

Explanation:

First we <u>calculate the temperature difference</u>:

  • ΔT = 100 °C - 50 °C = 50 °C

Then we can <u>calculate the heat released</u> by using the following formula:

  • q = Cp * ΔT * m

Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.

We <u>input the data</u>:

  • q = 0.239 J/g°C * 50 °C * 10.0 g
  • q = 119.5 J
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Wat is significant figures
Sav [38]

<em>Answer:</em>

  •                   0.052301 km have 5 significant figure
  •                   400 cm have 1 significant figure
  •                   50.0 m  have 3 significant figure
  •                  4500.01 ml have 6 significant figure

<em>Explanation:</em>

According to rules of significant figure

0.052301 km have 5 significant figure:

  • Zero to the left of the first non zero digit not significant.
  • Zero between the non zero digits are significant.

<em>400 cm have 1 significant figure:</em>

  • Trailing zeros are not significant in numbers without decimal points.

<em>50.0 m  have 3 significant figure:</em>

  • Trailing zeros are significant in numbers when there is decimal points.

<em>4500.01 ml have 6 significant figure:</em>

  • Zero between the non zero digits are significant.
4 0
3 years ago
44.8% of a 250. mL acid solution is used in an experiment, what volume of acid (in mL) was used?
postnew [5]

Answer:

112 mL  

Explanation:

The formula for percent by volume is

\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%

If you have 250 mL of a solution that is 44.8 % v/v,

\begin{array}{rcl}44.8\, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\44.8 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{44.8 \times 250\text{ mL}}{100}\\\\ & = & \textbf{112 mL}\\\end{array}

7 0
3 years ago
1. Do you think that the lightbulb and the Moon spheres are "to scale" compared to the real
Tems11 [23]

Answer:

Yes

Explanation: Had a question like this and I said yes and got it right

3 0
2 years ago
How many moles are in 2.12g Cr2O3
ohaa [14]

Answer:

0.01395mol Cr2O3

Explanation:

the molar mass of Cr2O3 is 151.9904 g/mol

2.12g Cr2O3 x 1 mol/151.9904g = 0.01395mol Cr2O3

4 0
2 years ago
Label the states of each compound in the reaction below.
devlian [24]

Answer:

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

Explanation:

CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄

To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:

In solution, CuSO₄ and KOH will dissociate as follow:

CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)

KOH (aq) —> K⁺ (aq) + OH¯(aq)

CuSO₄(aq) + KOH (aq) —>

Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)

Note: Cu(OH)₂ is insoluble in water.

Therefore, the elemental equation is:

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

8 0
3 years ago
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