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alexandr1967 [171]
3 years ago
10

Calculate the cost of 1.00 g of gold if the price gold is 655.00 per oz

Chemistry
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

$22.92

Explanation:

To solve this problem, you should convert the units to have the same in each quantity.

First we are going to convert from grams (g) to ounces (oz):

1.00g*\frac{1oz}{28.34g}=0.035oz

It means that there are 0.035 ounces in 1 gram.

Then you should multiply that value by the price of gold that is given in ounces (oz):

0.035ozGold*\frac{655.00}{1ozGold}=22.92

That is the price of 1.00 gram of gold is $22.92

Anna007 [38]3 years ago
3 0

Answer:

22.96 $ per 1 g of gold

Explanation:

We know that 1 g is equal to 0.035 oz.

Now we formulate the following reasoning:

if         1 oz of gold have a value of 655 $

then    0.035 oz of gold have a value of X $

X = (0.035 × 655) / 1 = 22.96 $

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The concentration of iron in ppb is 5.2 ppb

In atmospheric chemistry, PPM( parts per million) and PPB( parts per billion) units are used to express the concentration of gases. PPB stands for parts per billion, while PPM stands for parts of gas per million parts of air.

2.6 × 10⁻⁶ grams of iron in 500 ml of water.

Now, converting milliliter into liter:

500 mL = 500 mL × ( 1L / 1000 mL ) = 0.5 L

Now for ppm, mass must be in mg.

2.6 × 10⁻⁶ grams = 2.6 × 10⁻⁶ grams × ( 1000 mg / 1 grams ) = 2.6 × 10⁻³ mg

Then, the concentration of iron in ppm will be:

2.6 × 10⁻³ mg / 0.5 L = 5.2 × 10⁻³ ppm

Now, 1 ppm = 1000 ppb

Therefore,

5.2 × 10⁻³ ppm × 10³ = 5.2 ppb

Learn more about concentration here:

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