Answer:
20
Step-by-step explanation:
Total no = 75
N (P) = 48 , N (H) = 45 , N (T) = 58
N (P∩H) = 28 , N (H∩T) = 37 , N (P∩T) = 40
N (P∩H∩T) = 25
Total no = N (P) + N (H) + N (T) - N (P∩H) - N (H∩T) - N (P∩T) + N (P∩H∩T) + neither
75 = 48 + 45 + 58 - 28 - 37 - 40 + 25 + neither
75 = 71 + neither → neither = 4
N (only P) = N (P) - N (P∩H) - N (P∩T) + N (P∩H∩T) = 48 - 28 - 40 + 25 = 5
N (only H) = N (H) - N (P∩H) - N (H∩T) + N (P∩H∩T) = 45 - 28 - 37 + 25 = 5
N (only T) = N (T) - N (H∩T) - N (P∩T) + N (P∩H∩T) = 58 - 37 - 40 + 25 = 6
So, total liking either one or neither = 4 + 5 + 5 + 6 = 20
Answer:
6
Step-by-step explanation:
i guess
1/36 since there are 6 sides on both dice you times them together or you could list out the options like 1-1 1-2 etc and count it out
6×6=36
Answer:
Step-by-step explanation:
Let the relation between the total number of candies (y) and number of bags (x) is,
y = mx + b
Here, b = Extra pieces of candies sitting outside the box.
m = Candies per box
From the question,
x = 4,(Number of bags are 4)
y = 4m + 4
If total number of candies are 36,
36 = 4m + 4
4m = 32
m = 8
Each bag will contain 8 candies.
Therefore, equation representing the relation is,
y = 8x + 4
Now complete the table by substituting the values of x,
x y
1 12
2 20
3 28
4 36
5 44
6 52
7 60
8 68
9 76
10 84
