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ASHA 777 [7]
3 years ago
7

Suppose I have a wooden cube, which I then split into eight equal pieces. If I give you two of those pieces, and then give you t

hree more, what fraction of the original cube do I have left? Express your answer in decimal form.
Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

0.375

Step-by-step explanation:

You would have 3/8 of the original cube left. 0.375 in decimal form.

vampirchik [111]3 years ago
5 0

Answer:

.625

Step-by-step explanation:

Since the amount of pieces are 8, and you gave 5 away, you have to divide 5 by 8. This gives you .625

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1 because 1 is my favorite number and it’s good for guessing
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Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
The population is decreasing at a rate of 5% per year. If the population is 30,000 today, what will the population be in 12 year
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Answer:

\triangle BOT \cong \triangle IEW

Step-by-step explanation:

We are given the following in the question:

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\triangle BOT \cong \triangle IEW

Proof:

\text{In }\triangle BOT \text{ and } \triangle IEW

we can write:

\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}

Hence, the two triangle are congruent by SAS congruency rule.

\triangle BOT \cong \triangle IEW

The attached image shows the two triangle.

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