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mamaluj [8]
3 years ago
7

Trevor wants a life insurance policy with a cash feature and one he can change the death benefits of without having to get a new

policy. What type of policy best fits this scenario
Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

un death somthing

Step-by-step explanation:

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4. Find the missing angle<br><br> PLS I NEEDDDD HELPPP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS.
Ainat [17]

Answer:

i’m not 100% sure, but i’m going to say it’s 30 degrees

Step-by-step explanation:

because ik that all triangles equal 180 degrees. if this is wrong, i’m so sorry.

3 0
3 years ago
What is the answer ​
aliya0001 [1]

Answer:

(4,5)

(6,2)

(2,4)

Step-by-step explanation:

just add 3 to x and 1 to y

3 0
3 years ago
Read 2 more answers
7. The graph of part of linear function g is shown on the grid. Which inequality best represents the domain of the part shown?​
PSYCHO15rus [73]

Answer:

a

Step-by-step explanation:

Domain means the change in x.

so the domain will be which values of x the fn goes through.

you can see the black line goes from -9 to 2 in x values.

the -9 isn't filled in, but the 2 is. filled in means it will be with an equals instead of without.

so x is between -9 and 2, 2 is with equals -9 is without,

so the first one.

3 0
3 years ago
How do I put Y+4=2/3(X+7) in <br>standard form
ahrayia [7]
I hope this helps you

8 0
3 years ago
Read 2 more answers
What is the probability that a group of five friends all have different birthdays? Show all of your work for full credit.
patriot [66]

Answer: 0.98630136986

Step-by-step explanation:

There are 365 possible birthdays. The key to assigning the probability is to think in terms of complements: “Two (or more) people share a birthday” is the complement of “All people in the group have different birthdays.” Each probability is 1 minus the other. What is the probability that any two people have different birthdays? The first person could have any birthday (p = 365÷365 = 1), and the second person could then have any of the other 364 birthdays (p = 364÷365). Multiply those two and you have about 0.9973 as the probability that any two people have different birthdays, or 1−0.9973 = 0.0027 as the probability that they have the same birthday. If you have a group of five, it would mean your equation would have to be (p=360÷365)

8 0
3 years ago
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