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gavmur [86]
4 years ago
10

4 people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper . Noor is

hoping to be chairperson and Qu is hoping to be treasurer. What is the probability that Noor is selected to be chairperson and Qu is selected to be treasurer?
Mathematics
1 answer:
aliina [53]4 years ago
8 0

Answer:

Step-by-step explanation:

Given that  four people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper

Since one person cannot serve two posts we have total number of ways

= 4(3)(2)(1) = 24

If Noor is chair person and Qu treasurer then remaining 2 can take two posts in 2 different ways

So probability that Noor is selected to be chairperson and Qu is selected to be treasurer

=favourable outcomes/total outcomes

= \frac{2}{24} \\=0.083

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Answer:

140 in.³

Step-by-step explanation:

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3 years ago
Find the value of x of this question ​
mel-nik [20]
<h3><u>Let's</u><u> </u><u>understand</u><u> </u><u>the concept</u><u>:</u><u>-</u></h3>
  • Here angle B is 90°
  • So \triangle ABC and \triangle ABD Are right angled triangle
  • So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

BD=BC+CD

\longrightarrowBD=9+6

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  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

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\therefore{\underline{\boxed{\bf x=17cm}}}

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3 years ago
If the product of two numbers is equal to zero then at least one of the numbers must be zero
Zarrin [17]

Answer:

True

Step-by-step explanation:

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3 years ago
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lana [24]
<h3>Answers:</h3>
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================================================

Explanation:

If y has an exponent of 2, 4, 6, etc (basically any even number) then it leads to having inputs with multiple outputs.

Consider something like y^2 = x. If x = 100, then y = 10 or y = -10 are possible. A function can only have exactly one y output for any valid x input. Similar issues happen for things like y^4 = x and so on. So this is why A and C are not functions.

The other equations do not have y values with such exponents, so we can solve for y and have each x input lead to exactly one y output. Therefore, they are functions.

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