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gavmur [86]
3 years ago
10

4 people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper . Noor is

hoping to be chairperson and Qu is hoping to be treasurer. What is the probability that Noor is selected to be chairperson and Qu is selected to be treasurer?
Mathematics
1 answer:
aliina [53]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that  four people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper

Since one person cannot serve two posts we have total number of ways

= 4(3)(2)(1) = 24

If Noor is chair person and Qu treasurer then remaining 2 can take two posts in 2 different ways

So probability that Noor is selected to be chairperson and Qu is selected to be treasurer

=favourable outcomes/total outcomes

= \frac{2}{24} \\=0.083

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Akimi4 [234]

Answer:

B.

\sqrt{256}  \: and \:  \sqrt{289}

Step-by-step explanation:

Explanation:

\sqrt{256 }  = 16 \\  \sqrt{289}  \:  = 17

5 0
2 years ago
You are given the equation 27bx7•cx8•7xd=455x27. If b and c are both integers greater than 1 and b less than cb
jolli1 [7]

Answer:

The question is not so clear and complete

Step-by-step explanation:

But for questions like this, since the equation has been given, what is expected is for us to make comparison, compare the RHS with the LHS or by method of comparing coefficients.

We follow the stated conditions since we are told that b and c are both integers which are greater than 1 and b is less than the product of cb. from these conditions, we can compare and get the values of b , c and d.

Another approach is to assume values, make assumptions with the stated conditions, however, our assumptions must be valid and correct if we substitute the assumed values of b, c and d in the equation, it must arrive at the same answer for the RHS. i.e LHS = RHS

5 0
3 years ago
6x44<br> hbgvtfwtydtwftdftwyfdywdwd
Ipatiy [6.2K]

Answer:

264

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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nlexa [21]

To find the length of a line given two points, we are going to use the distance formula, which is defined below:

D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

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The points in this problem are (2, 5) and (-1, 5). We can find the distance of DC by substituting these values into the distance formula and simplifying, as shown below:

D = \sqrt{(-1 - 2)^2 + (5 - 5)^2

  • Substitute values into formula

D = \sqrt{(-3)^2}

  • Combine like terms and then simplify 0^2 to 0

D = \sqrt{9}

  • Compute (-3)^2 = 9

D = 3

  • Compute \sqrt{9} = 3

The length of DC is 3.

7 0
3 years ago
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