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AleksandrR [38]
3 years ago
6

There are 6 blue marbles, 4 green marbles, and 2 red marbles. You choose 2 marbles. What is the chance that they will be blue?

Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

0.0152 probability

Step-by-step explanation:

first there are 12 marbles: odds are 2/12 = 1/6

Then, there are 11 marbles: odds are 1/11

So the odds of both of them being blue are: 1/6 * 1/11 = 0.0152

Please give brainliest thanks!

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<h2>A. $1171.05</h2>

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Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

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