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riadik2000 [5.3K]
2 years ago
5

The table below shows the results of a screening program organized by Level 300 students of the department physiotherapy of the

College Health Sciences of the University of Ghana. Complete the table and answer the questions below it using your understanding of probability and its applications to biomedical data.
True Diagnosis for presence of E. Coli

Test results Disease No Disease Total
Positive 35 15
Negative 10 60
Total

a. What is the efficiency of the test? 3 marks
b. What is the sensitivity of the screening kit? 3 marks
c. What is the specificity of the screening kit? 3 marks
d. What is the predictive value (PPV) of the test? 3 marks
e. What is the negative predictive value (NPV) of the test? 3 marks
(15 marks)
2. In double blinded randomized control trial for hypertensive patients attending Cocoa Clinic, thirty (30) 50-59-year-old were admitted into an intervention program for 6 weeks. During the trial, the average improvement in their systolic blood pressure was 15. The average improvement in systolic blood pressure in the general population of hypertensive patients is 20 with a standard deviation of 2.

i. What are the null and alternative hypotheses in this RCT? (2 marks)
ii. What tail is required in this test? (2 marks)
iii. What is the most appropriate statistical test for this study? (2 marks)
iv. State the assumptions of the test. (2 marks)
v. Test the above hypothesis using the appropriate statistical tool (7 marks)
Critical value =3.6
Mathematics
1 answer:
Vladimir [108]2 years ago
7 0
The correct answer is C because they are asking for the specific screening kit marks
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8 0
3 years ago
Which of the following is the sum of all the odd integers between 5 and 102?
STALIN [3.7K]

Answer:

2601

Step-by-step explanation:

The integers between 5 and 102 are

7, 9, 11, 13, 15, 17,19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99, 101

The sum of the odd intergers between 2 and 105 can be calculated as follows

= (N + 1/2)^2

= (101 + 1 /2) ^2

= (102/2)^2

= 51^2

= 2601

Hence the sum of the odd intergers between 5 and 102 is 2601

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