Solve. 2x-5=8x+7-x it's number 4 on the picture

Elan Coil [88]

The probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.

Given that based on a poll, 60% of adults believe in reincarnation, to determine, assuming that 5 adults are randomly selected, what is the probability that exactly 4 of the selected adults believe in reincarnation, and what is the probability that all of the selected adults believe in reincarnation, the following calculations must be performed:

0.6 x 0.6 x 0.6 x 0.6 x 0.4 = X
0.36 x 0.36 x 0.4 = X
0.1296 x 0.4 = X
0.05184 = X
0.05184 x 100 = 5.184

0.6 x 0.6 x 0.6 x 0.6 x 0.6 = X
0.36 x 0.36 x 0.6 = X
0.1296 x 0.6 = X
0.07776 = X
0.07776 x 100 = 7.776

Therefore, the probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.

Learn more in brainly.com/question/795909

5 0

2 years ago

You're playing a game when you defend your village from an orc invasion there are three characters elf hobbit or human and five

34kurt

The probability that you'll be a magic elf is $\frac{1}{15}$ or 6.66%.

Step-by-step explanation:

Step 1:

Let A be the event of you choosing an elf.

The probability of an event is given by dividing the number of favorable outcomes by the total number of outcomes.

Here the number of favorable outcomes is 1 and the total number of outcomes is 3 i.e. elf, hobbit or human.

The probability of choosing an elf, $P(A) = \frac{1}{3} .$

Step 2:

Let B be the event of you choosing magic as your defense.

In this situation, the number of favorable outcomes is 1 and the total number of outcomes is 5 i.e. magic, sword, shield, slingshot, or umbrella.

The probability of choosing magic as your defense, $P(B) = \frac{1}{5} .$

Step 3:

The probability of both events A and B happening, we multiply the individual probabilities.

$P(getting a magic elf) = (P(A))(P(B)) = (\frac{1}{3} )(\frac{1}{5} ) = \frac{1}{15} = 6.66\%.$

8 0

3 years ago

Which of the following is a valid exclusion for the algebraic expression

zheka24 [161]

Answer:

4a^2b-8ab^2

Step-by-step explanation:

3 0

3 years ago

Round 368cm to the nearest meter

Bogdan [553]

4 metres hihiihiihiihihiihihiihiihihiihihiihiihiihiihihiihihiihiihi

4 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

Solve. 2x-5=8x+7-x it's number 4 on the picture​

Solve. 2x-5=8x+7-x it's number 4 on the picture