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kogti [31]
3 years ago
6

What’s the solution of 1,200-5(3x+30)=600

Mathematics
1 answer:
Elis [28]3 years ago
6 0
Hope this helps:

Answer: x = 30

Have a great day.
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Alicia has 32 stickers this is 4 times as many stickers as Benita has how many stickers does Benita have
Nikitich [7]
32 divided by 4 is 8. Benita has 8 stickers
7 0
3 years ago
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Find the rate of change of the function h(x) = 2 x on the interval 2 ≤ x ≤ 4
dangina [55]
For a linear function, the instantaneous rate of change is everywhere equal to the slope. Thus the rate of change of the function h(x)=2x on the interval 2≤x≤4
The rate of change of the function given will equal to its slope, thus;
slope,m=(y-1-y)/(x_1-x)
=(2*4-2*2)/(4-2)
=(8-4)/2
=4/2
=2

the answer is 2 
7 0
3 years ago
You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
3 years ago
What is a common tool between length and mass
Tema [17]
Seems like a wordplay question.

A "scale" is used for measuring length.

A different sort of "scale" is used for measuring mass.
8 0
3 years ago
Square root of 4×-1=5
borishaifa [10]

Answer:3/2

how i did this

​ Add 11 to both sides.

4x=5+1

Simplify 5+15+1 to 66.

4x=6

Divide both sides by 4

       x=   6/4

Simplify 6/4 to 3/2

       Awnser

x=3/2

Sorry if not helpful just trying my best :)

​​  

5 0
3 years ago
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