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3 years ago

Please help quick im offering 10pts and brainliest answer

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

Answer: The value of x is 30

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Angle PJK and Angle DJB are vertical angles. They are formed when you cross PD and KB. They are opposite one another. Vertical angles are congruent, so,

(angle PJK) = (angle DJB)
3x-40 = 2x-10
3x-40-2x = 2x-10-2x ... subtract 2x from both sides
x-40 = -10
x-40+40 = -10+40 .... add 40 to both sides
x = 30

Side Note:
if x = 30, then angle PJK is...
angle PJK = 3x-40
angle PJK = 3*x-40
angle PJK = 3*30-40
angle PJK = 90-40
angle PJK = 50 degrees
which is also the measure of angle DJB

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

PLEASE HELP WILL MARK BRAINLY

Alenkinab [10]

Answer:

1: $53750

2: $15975

3: 40

4: 90

5: 51

6a: 20%

6b:204

Step-by-step explanation:

1: to calculate this mulitply 50000*1.075= 53750

2: same deal 15000*1.065=15975

3: We have a ratio of 3:2 and then 60:x because we multiplied the first ratio by 20 to get the 60 in the second we multiply the 2 by 20 as well and get x=40

4: This one is kind of tricky. we know that there are 4 dogs for every 3 cats. We also know that there are 210 animals. This means that 4x+3x=210 solve this and get x=30 you then multiply the ratio 4:3 by 30 and get 120:90

5: 1/5*255=51

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3 years ago

Read 2 more answers

A recipe submitted to a magazine by one of its subscribers’ states that the mean baking time for a cheesecake is 55 minutes. A t

EastWind [94]

Answer:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55.

Step-by-step explanation:

Information given

We have the following data: 54 55 58 59 59 60 61 61 62 65

The sample mean and deviation can be calculated with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X-i -\bar x)^2}{n-1}}$

$\bar X=59.4$ represent the sample mean

$s=3.239$ represent the sample standard deviation

$n=10$ sample size

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to test if the true mean is higher than 55, the system of hypothesis would be:

Null hypothesis: $\mu \leq 55$

Alternative hypothesis: $\mu > 55$

Replacing the info given we got:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing the info given we got:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55

8 0

4 years ago